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kifflom [539]
3 years ago
5

A certain pyramid has a square base measuring 846 feet on a side and a height of 480 feet. a. What is the volume of the pyramid,

in cubic yards P.S. If anyone knows about the username playbloy please leave a comment below
Mathematics
2 answers:
WARRIOR [948]3 years ago
7 0

Answer:Area=L^2--->855^2 m^2

volume=Area*height ---> (855^2)(504)=368.43*10^6 m^3

Step-by-step explanation:

Goshia [24]3 years ago
3 0

Answer:

Step-by-step explanation:

Answer 1326

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Suppose you are saving your money to pay for a vacation for your family. so far, you have saved. you plan on saving more each mo
nekit [7.7K]

440 repeat 11 more times.

400+(400*.1)=440 repeat 11 more times. Remember to use a new value each time.

Vacations can get expensive fast. The average cost per person for a week-long vacation is about $1,200 annually. So, if you've got a family of five, you'll need to sock away at least $6,000 for transportation, hotels, meals, and amusement parks.

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3 0
2 years ago
A rectangle has a side length of two and seven eighths feet and a side width of 5 feet. What is the area of the rectangle?
Elza [17]

Answer:

14 3/8 ft^2

Step-by-step explanation:

Area = length * width

=   2 7/8 * 5

=  23/8 * 5

= 115/8

= 14 3/8 ft^2.

6 0
2 years ago
The saddest thing about betrayal is that it never comes from enemies
Xelga [282]

Answer:

you know you really need to watch what you say that comes out of your mouth

4 0
3 years ago
Read 2 more answers
Can u guys help me with #1
12345 [234]

Answer:

4.5 cups

Step-by-step explanation:

two quarters = 1/2

(1/2)*9=4.5

5 0
3 years ago
Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the
ziro4ka [17]

Answer:

a) \frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=9-1=8

The Confidence interval is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and the critical values are:

\chi^2_{\alpha/2}=20.09

\chi^2_{1- \alpha/2}=1.65

And replacing into the formula for the interval we got:

\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0
4 years ago
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