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3 years ago

7

Fill in the missing numbers to find two equivalent fractions 4/5 please help !!

1 answer:

konstantin123 [22]3 years ago

7 0

First fill in the blank box is 2 second is 8 third is 80

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B8%7D" id="TexFormula1" title="\frac{5}{8}" alt="\frac{5}{8}" align="absmiddle

bija089 [108]

Answer:

$\frac{5}{12}$

Step-by-step explanation:

Multiply straight across and reduce.

$\frac{5}{8}$ · $\frac{2}{3}$ = $\frac{10}{24}$ = $\frac{5}{12}$

6 0

3 years ago

⚠️⚠️⚠️⚠️⚠️help⚠️⚠️⚠️⚠️⚠️

mestny [16]

Answer:

u have it right it increases by 1:75 per time

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the measure of x and y (3x-3) (4y+4) 60 degrees

denis23 [38]

Answer:

b is the right answer

Step-by-step explanation:

5 0

3 years ago

What are the first three terms of a geometric sequence in which as = 25 and the common ratio is 5?

marin [14]

Answer:

The first three terms are: 25, 125 and 625

Step-by-step explanation:

Given

$a =25; r = 5$

Required

The first three terms

The nth term of a geometry progression is:

$T_n =ar^{n-1$

So, we have:

First term: $n = 1$

$T_n =ar^{n-1$

$T_1 =25 * 5^{1-1$

$T_1 =25 * 5^0$

$T_1 =25 * 1$

$T_1 =25$

Second term: $n = 2$

$T_n =ar^{n-1$

$T_2 =25 * 5^{2-1$

$T_2 =25 * 5^{1$

$T_2 =25 * 5$

$T_2 =125$

Third term: $n = 3$

$T_n =ar^{n-1$

$T_3 =25 * 5^{3-1$

$T_3 =25 * 5^{2$

$T_3 =25 * 25$

$T_3 =625$

7 0

3 years ago

Complete the table of values for f (2) = 2x^2+ 6x– 8 using Desmos.

spin [16.1K]

Answer:

Here you are. I hope this helps.

7 0

3 years ago

Read 2 more answers