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valkas [14]
2 years ago
13

PLEASE HELP!!! WHOEVER GETS THE ANSWER RIGHT GETS BRAINLIEST!!!

Mathematics
2 answers:
masha68 [24]2 years ago
7 0

There is 4 X so you use 360- (11+1) which is 348 and now divide by 4 which is now 87

<h2>Thank you for asking</h2><h2 /><h2>From Cambridge</h2><h2 />
prisoha [69]2 years ago
7 0

Answer:

42

Step-by-step explanation:

3x+1+x+11 = 180

4x+12 = 180

4x= 180-12

4x=168

x = 168/4

x = 42

You might be interested in
A total of tickets were sold for the school play. They were either adult tickets or student tickets. The number of student ticke
PSYCHO15rus [73]

Answer:

the number of adult ticket sold is 107 tickets

Step-by-step explanation:

The computation of the number of adult ticket sold is shown below:

Let us assume the number of tickets be x,

So, the adult be x

And for student it would be 3x

Students= 2x

Adults= x

Total = 4x

Now the equation could be

4x = 428

x = 107

This x signifies the adult tickets sold i.e 107

Hence, the number of adult ticket sold is 107 tickets

4 0
3 years ago
The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Appr
Kobotan [32]

Answer:

%  change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

T = 2.5 x + 0.5 x^{2}

We will approximate this distance  using the relation

f (x + dx) = f (x)+ f' (x)dx

dx = 26 - 25 = 1

T' =  2.5 + x

Therefore

f(x)+f'(x)dx = 2.5x+ 0.5x^{2} + 2.5 +x

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× 25^{2} + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 × 25^{2}

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

%  change in stopping distance = \frac{27.5}{375} × 100

%  change in stopping distance = 7.34 %

6 0
3 years ago
Can i have help please NO LINKS!!​
seropon [69]

Answer: 115 miles

Step-by-step explanation:

just do 60+55 miles = 115

3 0
2 years ago
Read 2 more answers
Select the correct text In the table.
Yuri [45]

Answer:

-9-958

216

Step-by-step explanation:

add

3 0
2 years ago
1. Mark and Bill have a combined weight of 170
qwelly [4]
<h3>Equation : x + y = 170 and y = 2x - 40</h3><h3>The weight of Bill is 70 pounds and weight of mark is 100 pounds</h3>

<em><u>Solution:</u></em>

Let the weight of Bill be "x"

Let the weight of mark be "y"

Given that,

Mark and Bill have a combined weight of 170  pounds

Therefore,

x + y = 170 ------- eqn 1

Mark weighs 40 pounds less than twice Bill's  weight

y = 2x - 40 ------- eqn 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x + 2x - 40 = 170

3x = 170 + 40

3x = 210

x = 70

<em><u>Substitute x = 70 in eqn 2</u></em>

y = 2(70) - 40

y = 140 - 40

y = 100

Thus weight of Bill is 70 pounds and weight of mark is 100 pounds

6 0
3 years ago
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