Answer:
the number of adult ticket sold is 107 tickets
Step-by-step explanation:
The computation of the number of adult ticket sold is shown below:
Let us assume the number of tickets be x,
So, the adult be x
And for student it would be 3x
Students= 2x
Adults= x
Total = 4x
Now the equation could be
4x = 428
x = 107
This x signifies the adult tickets sold i.e 107
Hence, the number of adult ticket sold is 107 tickets
Answer:
% change in stopping distance = 7.34 %
Step-by-step explanation:
The stooping distance is given by
We will approximate this distance using the relation
dx = 26 - 25 = 1
T' = 2.5 + x
Therefore
This is the stopping distance at x = 25
Put x = 25 in above equation
2.5 × (25) + 0.5× 
+ 2.5 + 25 = 402.5 ft
Stopping distance at x = 25
T(25) = 2.5 × (25) + 0.5 ×
T(25) = 375 ft
Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft
% change in stopping distance = 
× 100
% change in stopping distance = 7.34 %
Answer: 115 miles
Step-by-step explanation:
just do 60+55 miles = 115
Answer:
-9-958
216
Step-by-step explanation:
add
<h3>Equation : x + y = 170 and y = 2x - 40</h3><h3>The weight of Bill is 70 pounds and weight of mark is 100 pounds</h3>
<em><u>Solution:</u></em>
Let the weight of Bill be "x"
Let the weight of mark be "y"
Given that,
Mark and Bill have a combined weight of 170 pounds
Therefore,
x + y = 170 ------- eqn 1
Mark weighs 40 pounds less than twice Bill's weight
y = 2x - 40 ------- eqn 2
<em><u>Substitute eqn 2 in eqn 1</u></em>
x + 2x - 40 = 170
3x = 170 + 40
3x = 210
x = 70
<em><u>Substitute x = 70 in eqn 2</u></em>
y = 2(70) - 40
y = 140 - 40
y = 100
Thus weight of Bill is 70 pounds and weight of mark is 100 pounds
