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RUDIKE [14]
3 years ago
6

Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two thirds the

distance from point P to point R.
4.9

4.7

2.5

2.3

PLS HELP
Mathematics
1 answer:
Sladkaya [172]3 years ago
5 0
7 + (0-7) * 2/3 = 7 - 14/3 = (21 - 14) / 3 = 7/3 = 2.3
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Katarina [22]

Answer:

Tommy had 56 cents in start and Loren had 7 cents in start.

Step-by-step explanation:

Let,

x be the money Tommy have.

y be the money Loren have.

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Tommy had 8 times more money than Loren.

x = 8y     Eqn 1

Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore

x-14=y+35    Eqn 2

Putting x=8y in Eqn 2

8y-14=y+35\\8y-y=35+14\\7y=49

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\frac{7y}{7}=\frac{49}{7}\\y=7

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Hence,

Tommy had 56 cents in start and Loren had 7 cents in start.

6 0
3 years ago
The slope of the lines that passes through the points (-10,0) and (-13,3)
goldenfox [79]

Answer:

-1

Step-by-step explanation:

The formula to find the slope of a line is:

\frac{y_{2}- y_{1} }{x_{2} -x_{1} }

where (x1, y1) and (x2, y2) are points on the line. We can substitute the points (-10, 0) and (-13, 3) into the formula and simplify:

\frac{3-0}{-13-(-10)} =\frac{3}{-13+10} =\frac{3}{-3} =-1

This means the slope of the line is -1.

4 0
3 years ago
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