the sum of 2 numbers is 49. Twice the smaller number is 97 less than 3 times the larger number. What are the numbers?
1 answer:
Answer:
let the larger and smaller number be x and y respectively
first condition
x + y = 49
second condition
3x = 2y+97
3x-2y =97
Multiplying first condition by two and adding both equations
2x + 2y = 98
<u>3x -2y = 97</u>
5x = 195
x = 195/5 = 39
putting the value of x in
x + y = 49
y = 49 -39 = 10
again
Step-by-step explanation:
You might be interested in
Answer:
Solve X
X=1/2 X=0.5
Solve V
W=0.0260416v
V=38.4W
To find the derivative, you must use the chain rule.
If u=x^3+2x:
dy/dx=(dy/du)(du/dx)
dy/du=d/du(e^u)=e^u=e^(x^3 + 2x)
du/dx =d/dx (x^3+2x) = 3x^2 + 2
So dy/dx=
e^(x^3+2x) * (3x^2+ 2)
I’m just trynna get points
Answer:
16 + 2x
Step-by-step explanation:
Answer:
2x + 6
Step-by-step explanation:
= 2(x + 3)
= 2(x) + 2(3)
= 2x + 6
