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PolarNik [594]
3 years ago
12

John cut a paper square with a perimeter of 18 inches into two rectangles. The perimeter of one of the rectangles is 10 inches.

What is the perimeter of the second rectangle?
Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

13.5 inches

Step-by-step explanation:

Perimeter of the paper square = 18inches

Perimeter of a square = 4s

4s = 18 inches

s = 18/4 = 4.5 inches

Therefore, each side of the square = 4.5 inches.

When the square is cut into 2 rectangles,

The perimeter of one of the rectangles is 10 inches.

Perimeter of the second rectangle = 2L + 2W

Let the length of the rectangle (L) = one side of the square = 4.5 inches

Width of the Rectangle = Length of the square/2 = 4.5 inches/ 2 = 2.25

Perimeter of the second rectangle = 2(4.5) + 2(2.25)

= 9 + 4.5

= 13.5 inches

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Answer:

a) add x , subtract 1 and divide by 4

The solution of given equation x = \frac{3}{4}

<u>Step-by-step explanation:</u>

Given equation  1+3 x  = -x +4

                <em>  Add 'x' on both sides , we get</em>

                     1 + 3 x + x = - x + x +4

                     1 + 4 x  = 4

      <em>  Subtract '1' on both sides , we get</em>

<em>                     1+4 x -1 = 4 -1</em>

                         4 x = 3

<em>       Dividing '4' on both sides, we get</em>

                          \frac{4x}{4} = \frac{3}{4}

                          x = \frac{3}{4}

<u><em>Final answer</em></u>:-

<em>The solution of given equation </em>x = \frac{3}{4}<em></em>

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