A fleet of nine taxis is to be dispatched to three airports in such a way that three go to airport A, five go to airport B, and one goes to airport C. In how many distinct ways can this be accomplished?
2.44) Refer to Exercise 2.43. Assume that taxis are allocated to airports at random.
a) If exactly one of the taxis is in need of repair, what is the probability that it is dispatched to airport C?
b) If exactly three of the taxis are in need of repair, what is the probability that every airport receives one of the taxis requiring repairs?
So, my answer to 2.44a is 1/9. Hopefully this is correct at least :)
For 2.44b, my guess was
(3C1)(1/3)(2/3)2 * (5C1)(1/3)(2/3)4 * 1/3
The solutions manual on chegg (which seems to be riddled with errors) says something completely different. Is my calculation correct?
Answer: There would have to be 200 text messages fro both plans to cost the same each month.
Step-by-step explanation:
Because domain restrictions apply to this rational expression, x cannot be equal to {-2, 2}.
<h3>What is domain?</h3>
Domain restrictions are any points in the domain where the function will not have a value. This basically means that there is a point in the function where x will not work.
For the numerator, any value of x will suffice. We can have a value of 0 in the numerator, or a positive, negative, or decimal number.
However, the denominator cannot be equal to zero. This is due to the fact that a fraction bar represents division, and we cannot divide by zero.
Here,
x²-4=0
Add 4 to both sides:
x²-4+4 = 0+4
x² = 4
Take the square root of both sides:
√x² = √4
x = 2 or x = -2
The x cannot be equal to {-2, 2} as domain restrictions apply to this rational expression.
To know more about domain,
brainly.com/question/10238709
#SPJ4
Answer:
it is 61-28 but I not sure u can scan for any application to make sure u get it ur answer thx for
The width is x+2.
The length is x+4.
The area is the product of width and length.
.. Area = (x +2)(x +4)
.. = x^2 +6x +8
