Since in the above case, the beaker has two sections each with different radius and height, we will divide this problem into two parts.
We will calculate the volume of both the beakers separately and then add them up together to get the volume of the beaker.
Given, π = 3.14
Beaker 1:
Radius (r₁) = 2 cm
Height (h₁) = 3 cm
Volume (V₁) = π r₁² h₁ = 3.14 x 2² x 3 = 37.68 cm³
Beaker 2:
Radius (r₂) = 6 cm
Height (h₂) = 4 cm
Volume (V₂) = π r₂² h₂ = 3.14 x 6² x 4 = 452.16 cm³
Volume of beaker = V₁ + V₂ = 37.68 + 452.16 = 489.84 cm³
Answer:
x=−5.675726
Step-by-step explanation:
Answer:
Step-by-step explanation:
Eqn. 1 ----> 4y = x
Eqn. 2 ----> 5x-10y = -50
(Simplifying eqn.2 further)
(Substituting the value of x from eqn. 1)
Now, substituting the value of y in eqn. 1 ,
Answer:
-5≥x≤-1
Step-by-step explanation:
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