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VLD [36.1K]
3 years ago
11

"Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts​ (a) through​

(c) below. TInterval ​(13.046,22.15) x= 17.598 Sx = 16.01712719 n= 50 a. Express the confidence interval in the format that uses the​ ""less than"" symbol. Given that the original listed data use one decimal​ place, round the confidence interval limits accordingly."b. Identify the best point estimate of μ and the margin of error.
c. In constructing the confidence interval estimate of μ​, why is it not necessary to confirm that the sample data appear to be from a population with a normal​distribution?
A. Because the sample standard deviation is​ known, the normal distribution can be used to construct the confidence interval.
B. Because the sample is a random​ sample, it can be assumed that the sample mean is from a population with a normal distribution.
C.Because the population standard deviation is​ known, the normal distribution can be used to construct the confidence interval.
D. Because the sample size of 50 is greater than​ 30, it can be assumed that the sample mean is from a population with a normal distribution.
Mathematics
1 answer:
Stella [2.4K]3 years ago
6 0

Answer:

it is not necessary to confirm that the sample data appear to be from a population with a normal ​distribution;

D. Because the sample size of 50 is greater than​ 30, it can be assumed that the sample mean is from a population with a normal distribution

Step-by-step explanation:

Normal distribution which is  otherwise known as the Gaussian distribution, it is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.

The arithmetic mean or average; is the sum of a collection of numbers divided by the total  numbers in the collection.

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3 years ago
The test statistic of z= -2.39 is obtained when testing the claim that p<0.52.
krek1111 [17]

Considering the situation described, we have that:

a) The critical value is of z = -1.645.

b) Since the test statistic is less than the critical value, we should reject the null hypothesis H0.

<h3>What is the critical value?</h3>

We have a left-tailed test, as we are testing if the proportion is less than a value. Hence the critical value is z with a p-value equals to the significance level, hence z with a p-value of 0.05, hence z = -1.645.

<h3>What is the decision?</h3>

Considering the test statistic, for a left-tailed test, we have that:

  • Less than the critical value: Reject H0.
  • Equal or greater: Do not reject.

In this problem, z = -2.39 is less than -1.645, hence we should reject the null hypothesis H0.

More can be learned about the test of an hypothesis at brainly.com/question/13873630

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6 0
2 years ago
Can you please help me with this?
Crazy boy [7]

Answer:

A

Step-by-step explanation:

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This is answer A.

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9514 1404 393

Answer:

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Step-by-step explanation:

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