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sergiy2304 [10]
3 years ago
8

According to the National Association of Realtors, it took an average of three weeks to sell a home in 2017 . Data for the sale

of 40 randomly selected homes sold in Greene County, Ohio, in 2017 showed a sample mean of 3.6 weeks with a sample standard deviation of 2 weeks. Conduct a hypothesis test to determine whether the number of weeks until a house sold in Greene County differed from the national average in . Round your answer to four decimal places.
Mathematics
2 answers:
USPshnik [31]3 years ago
8 0

Answer:

heheujejeue had the dur hu d dhd

Step-by-step explanation:

yudheyeuueud hide dyed d

ikadub [295]3 years ago
3 0

Answer:

Step-by-step explanation:

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X=<br> - 6 2/3<br> - 9<br> - 12<br> please help asap
Nastasia [14]

Answer:

Step-by-step explanation:

x=12

4 0
3 years ago
Suppose babies born in a large hospital have a mean weight of 3242 grams, and a standard deviation of 446 grams. If 107 babies a
777dan777 [17]

Answer:

64.76% probability that the mean weight of the sample babies would differ from the population mean by less than 40 grams

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 3242, \sigma = 446, n = 107, s = \frac{446}{\sqrt{107}} = 43.12

What is the probability that the mean weight of the sample babies would differ from the population mean by less than 40 grams

This is the pvalue of Z when X = 3242 + 40 = 3282 subtracted by the pvalue of Z when 3242 - 40 = 3202

X = 3282

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3282 - 3242}{43.12}

Z = 0.93

Z = 0.93 has a pvalue of 0.8238.

X = 3202

Z = \frac{X - \mu}{s}

Z = \frac{3202 - 3242}{43.12}

Z = -0.93

Z = -0.93 has a pvalue of 0.1762

0.8238 - 0.1762 = 0.6476

64.76% probability that the mean weight of the sample babies would differ from the population mean by less than 40 grams

5 0
3 years ago
Please Help!! I will give 10 points and brainliest..
docker41 [41]

Answer:

I would go for D

6 0
3 years ago
Find the area of the shaded portion in the square. Show all work for full credit.
kumpel [21]
Well, what I would do [not sure if it's the correct way], is use the white area as a sector of a circle. The top right of the box is the center of the circle, so the radius is 6.
Then, by the white portion being one quarter of the circle (90° out of 360°), I could calculate the that pink shaded region = the total square (6×6) minus the white sector.
So area (A) of white sector (s): A(s) = 1/4×pi×r^2
A(s) =  \frac{\pi {r}^{2} }{4}  =  \frac{\pi  \times {6}^{2} }{4}  \\ A(s) =  \frac{36\pi}{4}  = \frac{9\pi}{1}  = 9x3.142 \\ A(s) = 28.27
36 - 28.27 = 7.73
6 0
3 years ago
Read 2 more answers
Of students in the AP curriculum at a prep school, 40% take one AP exam, 45% take two AP exams, and the remaining 15% take 3 AP
aliya0001 [1]

It should be noted that the probability that a student will earn at least one 5 will be 0.3152.

<h3>How to calculate the probability</h3>

Test P(x). P(at least one 5)

1. 0.4. 0.2

2. 0.45. 0.36

3. 0.15. 0.488

Therefore, the probability that a student in the AP curriculum will earn at least one 5 will be:

= (0.4 × 0.2) + (0.45 × 0.36) + (0.15 × 0.488)

= 0.3152

In conclusion, the correct option is 0.3152.

Learn more about probability on:

brainly.com/question/24756209

8 0
3 years ago
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