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seraphim [82]
2 years ago
15

Two ships are near a buoy in the open ocean. One ship is 20 km due north of the buoy, and the other ship is 13.5 km due east of

the buoy.
Round the answer to the nearest tenth.
Mathematics
1 answer:
anastassius [24]2 years ago
6 0

Answer:

24 km is your answer

Step-by-step explanation:

Let x be the distance between the two ships.

Hypotenuse side = x km

Adjacent side = 13.5 km

Perpendicular side = 20 km

by using Pythagoras theorem:

x²= 13.5²+ 20²=582.25

x=√ 582.25

х =24.129857024 km

Therefore, the distance between two ships to the nearest tenth place is, 24.1 km

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If you doubled joes age and added 10 years he would still be younger than his uncle. His uncle is 51. Use inequalities to find h
CaHeK987 [17]

Answer:

He is 20 at oldest, or x\leq 20

Step-by-step explanation:

The first step in finding a possible age is:

Subtract 10 from 51, and you get 41. Divide by 2, and you get about 20.5.

This means Joe is younger than or 20 years old.

4 0
2 years ago
I really need help with 22 plz
gogolik [260]
If there are 272.5 rotations in a mile, and 5280 ft in a mile, then there are 5280 ft in 272.5 rotations. Divide 5280 by 272.5 gives us 19.4 ft/rotation.
That's the circumference of the wheel, and since c = πd, 19.4/π = d, d = 6.2 ft. The diameter of the wheel is how tall it is.

Does this help? Any questions?
8 0
3 years ago
The sum of 5 times a larger number and twice a smaller is 5. The difference of 4 times the larger and the smaller number is 4. F
Gemiola [76]

Answer:

1 and 0

Step-by-step explanation:

Let's call the smaller number x and the larger number y.

This means 5y+2x=5.

Also, 4y-x=4.

This is a system of equations. There are two main ways two solve this.

Method 1: Substitution

5y+2x=5

4y-x=4

Solve for one of the variables, then substitute it back into one of the equations to solve for the other variable.

I will take 4y-x=4 and solve for x.

4y=4+x

x=4y-4

Then substitute for x in the other equation and solve for y.

5y+2x=5

5y+2(4y-4)=5

5y+8y-8=5

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y=1

Now we can go back to our equation for x and substitute for y.

x=4y-4

x=4(1)-4=0

y, the larger number, is 1 and

x, the smaller number, is 0

Method 2: Elimination

5y+2x=5

4y-x=4

Change the equations so that the coefficient of one of the variables in an equation is opposite the one in the other equation. Then add the equations and solve for each variable.

If I multiply both sides of the second equation, 4y-x=4, by 2, the coefficient of x will become -2. In the first equation, the coefficient is 2, so they will become opposites.

4y-x=4

becomes

8y-2x=8

Now we have 5y+2x=5 and 8y-2x=8.

Add the sides of both equations to cancel the x values.

5y+2x+8y-2x=5+8

13y=13

y=1

like last time, we can substitute for y in any of the original equations to get x.

5y+2x=5

5(1)+2x=5

5+2x=5

2x=0

x=0

y, the larger number, is 1 and

x, the smaller number, is 0

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