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seraphim [82]
3 years ago
15

Two ships are near a buoy in the open ocean. One ship is 20 km due north of the buoy, and the other ship is 13.5 km due east of

the buoy.
Round the answer to the nearest tenth.
Mathematics
1 answer:
anastassius [24]3 years ago
6 0

Answer:

24 km is your answer

Step-by-step explanation:

Let x be the distance between the two ships.

Hypotenuse side = x km

Adjacent side = 13.5 km

Perpendicular side = 20 km

by using Pythagoras theorem:

x²= 13.5²+ 20²=582.25

x=√ 582.25

х =24.129857024 km

Therefore, the distance between two ships to the nearest tenth place is, 24.1 km

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Find the distance between A(1, -1) and B(4, 3).
Greeley [361]

Answer:

<h2>The answer is 5 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

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From the question the points are

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The distance between them is

|AB|  =   \sqrt{ ({1 - 4})^{2} +  ({ - 1 - 3})^{2}  }  \\  =  \sqrt{( { - 3})^{2} +  ({ - 4})^{2}  }  \\  =  \sqrt{9 + 16}  \\  =  \sqrt{25}  \:  \:  \:  \:  \:  \:  \:  \:  \\  = 5 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\

We have the final answer as

<h3>5 units</h3>

Hope this helps you

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