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Marianna [84]
3 years ago
14

Q.2*

Mathematics
1 answer:
Leona [35]3 years ago
7 0

i think the B is the answer

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Find the equation of a line through (2,-4) and (-7,-4)
steposvetlana [31]
---------------------------------------------
Find slope : 
---------------------------------------------
\text {Slope = }  \dfrac{-4 - (-4)}{-7-2}  =  \dfrac{0}{-9}  = 0

When the slope is 0, the graph is a horizontal line.

Equation of the graph is y = -4

------------------------------------------------------
Answer: y = -4
------------------------------------------------------

3 0
3 years ago
How do you write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1,1)
harkovskaia [24]
First you have to put it into point-slope form before you can write it in slope-intercept form which is y-y1=m(x-x1)

Y-1=2(x-1)
Distribute the 2 to the x and -1
Y-1=2x-2
Move it all to one side
Y=2x-1
7 0
3 years ago
Read 2 more answers
The base of an aquarium with given volume V is made of slate and the sides are made of glass. If the slate costs seven times as
Olin [163]

Answer:

x = ∛(2V/7)

y = ∛(2V/7)

z = 3.5 [∛(2V/7)]

{x,y,z} = { ∛(2V/7), ∛(2V/7), 3.5[∛(2V/7)] }

Step-by-step explanation:

The aquarium is a cuboid open at the top.

Let the dimensions of the base of the aquarium be x and y.

The height of the aquarium is then z.

The volume of the aquarium is then

V = xyz

Area of the base of the aquarium = xy

Area of the other faces = 2xz + 2yz

The problem is to now minimize the value of the cost function.

The cost of the area of the base per area is seven times the cost of any other face per area.

With the right assumption that the cost of the other faces per area is 1 currency units, then, the cost of the base of the aquarium per area would then be 7 currency units.

Cost of the base of the aquarium = 7xy

cost of the other faces = 2xz + 2yz

Total cost function = 7xy + 2xz + 2yz

C(x,y,z) = 7xy + 2xz + 2yz

We're to minimize this function subject to the constraint that

xyz = V

The constraint can be rewritten as

xyz - V = 0

Using Lagrange multiplier, we then write the equation in Lagrange form

Lagrange function = Function - λ(constraint)

where λ = Lagrange factor, which can be a function of x, y and z

L(x,y,z) = 7xy + 2xz + 2yz - λ(xyz - V)

We then take the partial derivatives of the Lagrange function with respect to x, y, z and λ. Because these are turning points and at the turning point, each of the partial derivatives is equal to 0.

(∂L/∂x) = 7y + 2z - λyz = 0

λ = (7y + 2z)/yz = (7/z) + (2/y) (eqn 1)

(∂L/∂y) = 7x + 2z - λxz = 0

λ = (7x + 2z)/xz = (7/z) + (2/x) (eqn 2)

(∂L/∂z) = 2x + 2y - λxy = 0

λ = (2x + 2y)/xy = (2/y) + (2/x) (eqn 3)

(∂L/∂λ) = xyz - V = 0

We can then equate the values of λ from the first 3 partial derivatives and solve for the values of x, y and z

(eqn 1) = (eqn 2)

(7/z) + (2/y) = (7/z) + (2/x)

(2/y) = (2/x)

y = x

Also,

(eqn 1) = (eqn 3)

(7/z) + (2/x) = (2/y) + (2/x)

(7/z) = (2/y)

z = (7y/2)

Hence, at the point where the box has minimal area,

y = x,

z = (7y/2) = (7x/2)

We can then substitute those into the constraint equation for y and z

xyz = V

x(x)(7x/2) = V

(7x³/2) = V

x³ = (2V/7)

x = ∛(2V/7)

y = x = ∛(2V/7)

z = (7x/2) = 3.5 [∛(2V/7)]

The values of x, y and z in terms of the volume that minimizes the cost function are

{x,y,z} = {∛(2V/7), ∛(2V/7), 3.5[∛(2V/7)]}

Hope this Helps!!!

7 0
3 years ago
Please Help Can weather and climate be used interchangeably.
pickupchik [31]

Answer:

yes

'Weather' and 'climate' are used interchangeably.

Step-by-step explanation:

"Climate" describes the average atmospheric conditions over many years

the average annual rainfall, the predominant wind direction, or the season in which rain is likely to occur can be said as  Weather

<h2><u><em>hope it helps u</em></u></h2><h2><u><em>if it does so please mark me as brainiest </em></u></h2>
8 0
3 years ago
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Find the greatest common factor: 9a3bc2 + 12ac4 + 15a2b3c 3abc 15a3b3c4 3ac 9a2b2c2
VARVARA [1.3K]
The greatest common factor is 3abc
8 0
3 years ago
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