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3 years ago

What is the x for this problem??

Mathematics

1 answer:

solong [7]3 years ago

4 0

Answer:

Let's just find the value of the unknown degree next to 35 degrees.

180 - 35 = 145 degrees

Since 145 degrees is the unknown degree next to 35 degrees, it is vertical to the x it will be the same therefore your answer is 145 degrees.

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Bill makes leather shoes. He charges $45 for a pair of women's shoes and $50 for a pair of men's shoes. He sells x pairs of wome

Sav [38]

That is a very easy question the answer is:
2,500/50=

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3 years ago

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a. The position of a particle is given by x(t) = t3 - 3t2 - 96 +1. For what values oft is the particle at rest?

natita [175]

Answer:

t = 0 and t = 2

Step-by-step explanation:

It is at rest when the velocity = 0

The velocity is the 1st derivative

So, x'(t) = 3t^2 - 6t = 0

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3 years ago

5,000 x 300,000 +50 -300 +4,200 x 2 - 5 x 255 =

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Answer:

1500006875

Step-by-step explanation:

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3 years ago

Your blank should furnish enough money to live on, in an emergency, for six months

Bond [772]

C. Savings.

It's often recommended that you have a savings account/emergency fund with roughly 3-6 months worth of living expenses in case of an emergency.

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3 years ago

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A spherical balloon currently has a radius of 19cm. If the radius is still growing at a rate of 5cm or minute, at what rate is a

miv72 [106K]

Answer:

22670.8 cm³/min

Step-by-step explanation:

Given:

Radius of the balloon at a certain time (r) = 19 cm

Rate of growth of radius is, $\frac{dr}{dt}=5\ cm/min$

The rate at which the air is pumped in the balloon can be calculated by finding the rate of increase in the volume of the balloon.

So, first we find the volume of the sphere in terms of 'r'. As the balloon is spherical in shape, the volume of the balloon is equal to the volume of a sphere. Therefore,

Volume of balloon is given as:

$V=\frac{4}{3}\pi r^3$

Now, rate of increase of volume is obtained by differentiating both sides of the equation with respect to time 't'.

Differentiating both sides with respect to time 't', we get:

$\frac{dV}{dt}=\frac{d}{dt}(\frac{4}{3}\pi r^3)\\\\\frac{dV}{dt}=\frac{4\pi}{3}(3r^2)(\frac{dr}{dt})\\\\\frac{dV}{dt}=4\pi r^2(\frac{dr}{dt})$

Now, plug in 19 cm for 'r', 5 cm per minute for $\frac{dr}{dt}$ and solve for $\frac{dV}{dt}$ . This gives,

$\frac{dV}{dt}=4\pi (19 cm)^2(5\ cm/min)\\\\\frac{dV}{dt}=4\times 3.14\times 361\times 5\ cm^3/min\\\\\frac{dV}{dt}=22670.8\ cm^3/min$

Therefore, the rate at which the air is being pumped into the balloon is 22670.8 cm³/min.

4 0

4 years ago