Answer:
yes your absolutely right
Step-by-step explanation:
you just are
Let X be the national sat score. X follows normal distribution with mean μ =1028, standard deviation σ = 92
The 90th percentile score is nothing but the x value for which area below x is 90%.
To find 90th percentile we will find find z score such that probability below z is 0.9
P(Z <z) = 0.9
Using excel function to find z score corresponding to probability 0.9 is
z = NORM.S.INV(0.9) = 1.28
z =1.28
Now convert z score into x value using the formula
x = z *σ + μ
x = 1.28 * 92 + 1028
x = 1145.76
The 90th percentile score value is 1145.76
The probability that randomly selected score exceeds 1200 is
P(X > 1200)
Z score corresponding to x=1200 is
z = 
z = 
z = 1.8695 ~ 1.87
P(Z > 1.87 ) = 1 - P(Z < 1.87)
Using z-score table to find probability z < 1.87
P(Z < 1.87) = 0.9693
P(Z > 1.87) = 1 - 0.9693
P(Z > 1.87) = 0.0307
The probability that a randomly selected score exceeds 1200 is 0.0307
Answer:
3/500
Step-by-step explanation:
3/5 x 1%
=> 3/5 x 1/100
=> 3/500
Hope it helps you
Answer:
I cant see good
Step-by-step explanation:
Answer:
Step-by-step explanation:
- <em>A line segment that connects two midpoints of the sides of a triangle is called a midsegment.</em>
- <em>A triangle midsegment is parallel to the third side of the triangle and is half of the length of the third side.</em>
Point J is midpoint of side HI as HJ = JI
Point K is midpoint of side GI as GK = KI
JK is midsegment as connects the midpoints of the sides
JK = 1/2HG as per property of midsegment
- 6x - 4 = 10x/2
- 6x - 4 = 5x
- 6x - 5x = 4
- x = 4
JK = 6x - 4 = 6*4 - 4 = 24 - 4 = 20 m