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gladu [14]
3 years ago
10

The answer to the problem

Mathematics
2 answers:
GenaCL600 [577]3 years ago
7 0

Answer:

580

Step-by-step explanation:

ser-zykov [4K]3 years ago
4 0

Answer:

580

Step-by-step explanation:

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What would the variables for a and b be? 3/x + 5/x^2 = (ax+b)/x^2
allsm [11]

Answer:

a=3,b=5

Step-by-step explanation:

\frac{3}{x}  +  \frac{5}{ {x}^{2}  }  \\  =  \frac{3x}{ {x}^{2} }   +  \frac{5}{ {x}^{2} }  \\  =  \frac{3x + 5}{ {x}^{2} }

so as you got it:

\frac{(ax + b)}{ {x}^{2} }  =  \frac{3x + 5}{ {x}^{2} }  \\ a = 3 \\ b = 5

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3 years ago
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alexandr1967 [171]

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Evaluate 4.7j-6.8k when j=5 and k=3
creativ13 [48]

Answer:

3.1

Step-by-step explanation:

After substitution of the givens, the expression 4.7j-6.8k takes on the value

4.7(5) - 6.8(3) = 23.5 - 20.4 = 3.1

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3 years ago
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pav-90 [236]

Answer: When distance increases, gravity decreases.

When distance decreases, gravity increases.

This means they have an inversely proportional relationship.

Step-by-step explanation:

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3 years ago
Find the domain of where f(x) = x + 10 and g(x)=x².
ASHA 777 [7]

The domain of the function f(x)=x+10 is (-∞, ∞) and for the function g(x)=x² is (-∞, ∞).

<h3>What is meant by domain?</h3>

If a formula specifies a real function f, it may not be defined for some values of the variable. The natural domain or domain of definition of f is the set of real numbers on which the formula can be evaluated to a real number in this case. A partial function is often referred to just as a function, and its natural domain is referred to simply as its domain.

Given,  f(x) = x + 10

g(x)=x²

The domain for the function f(x)=x + 10

So, the domain of f(x)=x+10 is (-∞, ∞)

The domain for the function g(x)=x²

The expression's domain is only real numbers, with the exception of places where it is undefined. Because there is no real number in this scenario, the expression is undefined.

So, the domain of the function g(x)=x² is (-∞, ∞)

To know more about domain, visit:

brainly.com/question/28135761

#SPJ1

8 0
1 year ago
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