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Sidana [21]
2 years ago
15

the probabilities that Kojo and Adwoa will pass an examination are 3/4 and 3/5 respectively. Find the probability that both will

fail the examination​
Mathematics
1 answer:
olga_2 [115]2 years ago
5 0
Assuming that their exam success is independent then
P(both fail) = 1/4 x 2/5 = 2/20 or 1/10
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She spent $19.88 on cheese and bread
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A triangle has two sides of length 9 and 14 what is the smallest possible whole number length for the third side
melisa1 [442]

Let the third side = x.

The sum of any two sides must be greater than the third side

14 + 9 > x

  23 > x

14 + x > 9

   x > -5

9 + x > 14

   x > 5

So 5 < x < 23

6 0
2 years ago
Question 3(Multiple Choice Worth 3 points) (07.04) Ashley solved the exponential equation 3x+1 = 15 and her work is shown below.
Mademuasel [1]
She was not supposed to "undistribute" and separate 3x+1 she was supposed to subtract 1 from both sides

3 0
3 years ago
Read 2 more answers
Lily paints 3 trees for a wall mural the middle tree is 2 1/2 ft tall the tree on the left is 3/4as tall as the middle tree the
raketka [301]

Answer:

Middle: 2.5  ft

Right: 4,375  ft

Left: 1,875 ft

Step-by-step explanation:

We know that a tree in the middle is 2.5 feet tall.

Now the tree on the left measures 3/4 of the tree in the middle, therefore:

2.5 * 3/4 = 1.875

Which means that the tree on the left is 1.875 feet tall.

Finally the tree on the right 1 3/4, which would be 1.75 times the tree in the middle, therefore:

2.5 * 1.75 = 4.375

Therefore the tree on the right is 4.375 feet tall.

5 0
2 years ago
Read 2 more answers
The weights of soy patties sold by a diner are normally distributed. A random sample of 25 patties yields a mean weight of 4.2 o
just olya [345]

Answer:

t=\frac{4.2-4}{\frac{0.5}{\sqrt{25}}}=2

The degrees of freedom are given by:

df =n-1=25-1=24

And the p value would be given by:

p_v = P(t_{24}>2) =0.0285

And since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case is significantly hiher than 4. And the claim for this case is not appropiate      

Step-by-step explanation:

Data provided

\bar X=4.2 represent the sample mean for the weigths

s=0.5 represent the sample standard deviation

n=25 sample size      

\mu_o =4 represent the value that we want to analyze

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic

p_v represent the p value for the test

System of hypothesis

We want to conduct a hypothesis in order to check if the true mean weigth is less than 4 or not, the system of hypothesis would be:      

Null hypothesis:\mu \leq 4      

Alternative hypothesis:\mu > 4      

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

Replacing the info given we got:

t=\frac{4.2-4}{\frac{0.5}{\sqrt{25}}}=2  

The degrees of freedom are given by:

df =n-1=25-1=24

And the p value would be given by:

p_v = P(t_{24}>2) =0.0285

And since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case is significantly hiher than 4. And the claim for this case is not appropiate

5 0
3 years ago
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