Hello,
(tg(x))'=1/cos²(x)
(arcsin(x))'=1/√(1-x²)
cos²(arcsin(x))=1-sin²(arcsin(x))=1-x²
(tg(x))'=1/cos²(x)
(arcsin(x))'=1/√(1-x²)
cos²(arcsin(x))=1-sin²(arcsin(x))=1-x²
If f(x)=x2+x and g(x)=x-3, find f(g(7))
1 answer:
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Answer:
The sum of the first 47 terms of the series, 12, 16, 20, ... S₄₈ is 4,888
Step-by-step explanation:
The given series is;
12, 16, 20, ...,
Therefore, the first term of the series is, a = 12
The common difference of series is found as follows;
The difference between subsequent terms, 12 and 16 is 16 - 12 = 4
The difference between subsequent terms, 16, and 20 is 20 - 16 = 4
Therefore, the common difference, d = 4
The series is therefore an arithmetic projection, AP
The sum of the first 'n' terms of an AP, Sₙ, is given as follows;
(47/2)*(2*12+(47-1)*4)
The sum of the first 47 terms is therefore given as follows;
The sum of the first 47 terms of the series, 12, 16, 20, ... S₄₈ = 4,888
Answer:
His book was opened at Page no.296 and Page no.297
Step-by-step explanation:
Let the page number of one page be x
Page number of page facing page no. x = x+1
We are given that the product of the facing pages was 87,912.
So, x(x+1)=87912
(x+297)(x-296)=0
x=296,-297
Since Page no. cannot be negative
So, x=296
x+1=296+1=297
So, his book was opened at Page no.296 and Page no.297