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snow_tiger [21]
3 years ago
15

A string of decorative lights is 28 feet long. The first light on the string is 16 inches from the plug. If the lights on the st

ring are spaced 4 inches apart, how many lights are there on the string?
Mathematics
1 answer:
lilavasa [31]3 years ago
7 0
Well if there is 28 feet, that would be (12x28) 336 inches,  and 16 inches between the plug and the first light, there would be only 320 inches left for lights. therefore, if there are 4 inches between each light, we divide 320 by 4.  the answer we get is 80. there are 80 lights.
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d) 33.1 miles per gallon

Step-by-step explanation:

Mean = sum/ number

Mean= (48+25+35+34+33+37+32+34+23+30)/10 = 33.1

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2 years ago
The product of two given numbers is 126 both of them are divisible by 3 but neither of them is 3.The larger of the two numbers i
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pychu [463]

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8 0
2 years ago
) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

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x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

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\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

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8 0
3 years ago
Help plz i need this done
Romashka [77]

Answer:

x ≈ 11.5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] sin∅ = opposite over hypotenuse

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

Angle = 35°

Opposite Leg = <em>x</em>

Hypotenuse = 20

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [sine]:                    sin35° = x/20
  2. Isolate <em>x</em>:                                 20sin35° = x
  3. Evaluate:                                 11.4715 = x
  4. Rewrite:                                  x = 11.4715
  5. Round:                                    x ≈ 11.5
5 0
2 years ago
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