Answer:
The ordered pair that contains the solution to the equation lies in Quadrant I.
The solution to the equation is x=2
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Answer:
(x, y) = (3, 12)
Step-by-step explanation:
Using the given variable definitions, we can write the equations ...
y = x + 9
2(x +y) = 30
__
Solving the second equation for y, we have ...
y = 15 -x
Substituting this into the first equation gives ...
15 -x = x +9
6 = 2x . . . . . . . . . add x-9
3 = x . . . . . . . . . . divide by 2
y = 3+9 = 12 . . . . substitute into the first equation
The numbers are (x, y) = (3, 12).
Answer:

Step-by-step explanation:
We are told that the area of the bag can be represented by the function
and as the bag is raised up its height can be represented by the function
.
Since we know that we can find volume of cuboid by multiplying base area to its height. We are given area and height of bag as functions. Now we will find volume of the bag by multiplying these functions.

After using distributive property we will get,


Therefore, the collapsible bag can hold
grain.