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katrin [286]
3 years ago
15

In the figure to the right, you are given a square ABCD. Each of its sides is divided into two segments, such that AE = BF = CG

= DH. Prove that quadrilateral EFGH is a square.
△HAE≅△___ ≅△___ ≅△GDH by rule ___?

Mathematics
2 answers:
egoroff_w [7]3 years ago
6 0

Answer:

for the bottom part with hae and gdh the rule could also be LL (leg, leg)

Step-by-step explanation:


tensa zangetsu [6.8K]3 years ago
4 0
Proving that EFGH is a square: points E,F,G,H
separate the sides of the square ABCD into two lines. if AE=BF=CG=DH then
AH=DG=EB=FC and it shows that if we connect the points E,F,G,H to each other with line we will have a square

HAE~EBF~FCG~GDH by rule SAS

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diamong [38]

Answer:

17.1

Step-by-step explanation:

8 0
3 years ago
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Write the equation for the parabola that has x− intercepts (−2,0) and (4,0) and y− intercept (0,4).
seropon [69]

Answer:

y = -\frac{1}{2}(x^2-2x-8)

Simplified it is y=-\frac{1}{2}x^2+x+4

Step-by-step explanation:

The x-intercepts of a parabola form the factors of the equation. Since the x -intercepts are (-2,0) and (4,0) then the factors are (x+2) and (x-4). Factors are pieces which multiply to make the equation.

y=(x+2)(x-4)\\y=x^2+2x-4x-8\\y=x^2-2x-8

This is the standard form of the parabola ax^2+bx+c. Since the y-intercept of the parabola is (0,4) then a number must also be multiplied to it

y=a(x^2-2x-8)

We find a by plugging in x=0 and y=4.

4=a(0^2-2(0)-8)\\4=a(0-0-8)\\4=a(-8)\\\frac{4}{-8} = a\\\frac{-1}{2} = a

So the equation is y = -\frac{1}{2}(x^2-2x-8).

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3 0
3 years ago
15 points
Tems11 [23]

9514 1404 393

Answer:

  I, III

Step-by-step explanation:

You know from your study of the Pythagorean theorem that a triangle with sides 3, 4, and 5 will be a right triangle. Any scaled version of this triangle will also be a right triangle, so it is helpful to learn to recognize when scaled values of these numbers are used.

  I -- the scale factor for a 3-4-5 right triangle is 2/10

  II -- no isosceles right triangle has integer side lengths. (not a right triangle)

  III -- the scale factor for a 3-4-5 right triangle is 1/13

  IV -- the lengths do not form a triangle

Triangles I and III are right triangles.

_____

<em>Additional comment</em>

The sides of an isosceles right triangle have the ratios 1 : 1 : √2. The square root of 2 is irrational. No scaled version of this triangle can have rational side lengths.

6 0
3 years ago
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Harrizon [31]
It will be the sum of any two no. Which will give ans as 180 so i will conclude 90+90
Or 90 marks in both exams
4 0
3 years ago
Kara's Krafts is selling a set of paint brushes for 30% off their regular price of $28. Craft Emporium is selling the same set o
Delvig [45]

Answer: Craft Emporium(Based on what you told me)

Step-by-step explanation:

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Since this is $28 dollars:

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Since this is $25 dollars:

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3 0
3 years ago
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