Help please .. im not good in math

Write the standard form of an equation with p=3 sqrt2, theta= 135°

Arlecino [84]

Answer:

x - y + 6 = 0

Step-by-step explanation:

In normal form of a straight line, the equation is given by

$x\cos \theta + y\sin \theta = p$

where p is the perpendicular distance of the line from the origin and $\theta$ is the angle between the perpendicular line and the positive direction of the x-axis.

Here, in our case $p = 3\sqrt{2}$ and $\theta = 135$ Degree,

Therefore, the normal form of the straight line equation is

$x \cos 135 + y \sin 135 = 3\sqrt{2}$

⇒ $x \cos (180 - 45) + y \sin (180 - 45) = 3\sqrt{2}$

⇒ $- x \cos 45 + y \sin 45 = 3\sqrt{2}$ {Since, Cos (180 - Ф) = - Cos Ф and Sin (180 - Ф) = Sin Ф}

⇒ $- \frac{x}{\sqrt{2}} + \frac{y}{\sqrt{2}} = 3\sqrt{2}$

⇒ - x + y = 3√2 × √2 = 6

⇒ x - y + 6 = 0

So, the standard form of the equation is x - y + 6 = 0. (Answer)

7 0

4 years ago

What is the solution to the equation -2n -2 / 3 =12 ? n =

SVEN [57.7K]

The answer is n= -19/3

3 0

3 years ago

Subtract 1.05 from a certain number. Multiply the difference by 0.8, add 2.84 to the product then divide the sum by 0.01 and get

attashe74 [19]

Just do the whole process backwards
700*0.01=7
7-2.84=4.16
4.16/0.8=5.2
5.2+1.05=6.25

8 0

3 years ago

A random sample of 16 students selected from the student body of a large university had an average age of 25 years. We want to d

kenny6666 [7]

Answer:

$z=\frac{25-24}{\frac{2}{\sqrt{16}}}=2$

$p_v =2*P(Z>2)=0.0455$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean differs from 24 at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X=25$ represent the sample mean

$\sigma=2$ represent the sample population deviation for the sample

$n=16$ sample size

$\mu_o =24$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is different from 24, the system of hypothesis would be:

Null hypothesis: $\mu = 24$

Alternative hypothesis: $\mu \neq 24$

If we analyze the size for the sample is < 30 but we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{25-24}{\frac{2}{\sqrt{16}}}=2$

P-value

Since is a two sided test the p value would be:

$p_v =2*P(Z>2)=0.0455$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean differs from 24 at 5% of significance

6 0

3 years ago

How many units long is a segment whose endpoints are (-4,1) and (1,13)?

Ann [662]

Answer:

13

Step-by-step explanation:

(1−−4)2+(13−1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√(1++0)2+(13−1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√(5)2+(12)2‾‾‾‾‾‾‾‾‾‾‾√25+144‾‾‾‾‾‾‾‾‾√169‾‾‾‾√≈13

Sorry if the explanation is a bit confusing but, I used the distance formula to do this.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

7 0

3 years ago

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