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3 years ago

Need help asap will give brainly

Mathematics

2 answers:

Pavel [41]3 years ago

7 0

It’s the first bubble

chubhunter [2.5K]3 years ago

6 0

Answer:

Dilation

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Can someone plss help me I don't understand this!

Yanka [14]

Answer: 4. A

5. C

6. B

Step-by-step explanation:

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3 years ago

Write a simplified polynomial expression in standard form to represent the area of the rectangle below.

motikmotik

(5x+2)(x-4
5x (x)+2(x)+5x (-4)+2 (-4)
5x^2+2x-20x-8
5x^2-18x-8
C. 5x^2-18x-8

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4 years ago

Read 2 more answers

Find three solutions to the equation 2x+3y=12

aleksley [76]

Answer:

if x = 3, then y = 2

if x = 0, then y = 4

if x = 6, then y = 0

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3 years ago

In April, The Kazbaas drove 760 miles in their tour van.

DedPeter [7]

9514 1404 393

Answer:

£135.98

Step-by-step explanation:

$(760\text{ mi})\dfrac{1\text{ gal}}{29.5\text{ mi}}\cdot\dfrac{4.55\text{ L}}{1\text{ gal}}\cdot\dfrac{\pounds1.16}{1\text{ L}}=\dfrac{760\cdot4.55\cdot\pounds1.16}{29.5}\\\\=\boxed{\pounds135.98}$

It cost £135.98 for petrol in April.

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3 years ago

Lim x-1 x2 - 1/ sin(x-2)

balu736 [363]

Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

Explanation:

Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

Since $\lim_{x \to1}sin(x-2)\neq 0$

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

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3 years ago