Answer:
Option C is correct.
Step-by-step explanation:
y = x^2-x-3 eq(1)
y = -3x + 5 eq(2)
We can solve by substituting the value of y in eq(2) in the eq(1)
-3x+5 = x^2-x-3
x^2-x+3x-3-5=0
x^2+2x-8=0
Now factorizing the above equation
x^2+4x-2x-8=0
x(x+4)-2(x+4)=0
(x-2)(x+4)=0
(x-2)=0 and (x+4)=0
x=2 and x=-4
Now finding the value of y by placing value of x in the above eq(2)
put x =2
y = -3x + 5
y = -3(2) + 5
y = -6+5
y = -1
Now, put x = -4
y = -3x + 5
y = -3(-4) + 5
y = 12+5
y =17
so, when x=2, y =-1 and x=-4 y=17
(2,-1) and (-4,17) is the solution.
So, Option C is correct.
Answer:
21
Step-by-step explanation:
I did the math.
Acute would be less than 90 degrees, obtuse is greater than 90 degrees and right is 90 degrees
- Two angles that are complements of each other add to equal 90 degrees (they are complementary angles).
- One angle measures x degrees.
- The other angle measures 25 more than 4 times the angle that measures x degrees; it measures 4x + 25 degrees.
To find x, set the sum of these expressions (x and 4x + 25) equal to 90 and solve algebraically for x.
90 = x + (4x + 25)
90 = x + 4x + 25
90 = 5x + 25
65 = 5x
13 = x
If you wanted to find the measure of angle x, you'd substitute 13 for x in its expression, 4x + 25.
4x + 25
4(13) + 25
52 + 25
77
Answer:
x = 13
m∠x = 77°
