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Evgesh-ka [11]
3 years ago
11

Estimate [5 7/8 - 2 3/20] + 1 4/7​

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

change into improper fraction then do the problem then turn back into mixed number

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Pls help it’s easy but I been staring at this for 2 hours now pls help a lot of points and will give brainlyest
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Answer:?

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Step-by-step explanation:

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(10,2)

97.5

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C. x = -2

Step-by-step explanation:

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3 years ago
Please show step by step of working out the value of r for which is A is aminimum and calculate the minimum surface area of the
almond37 [142]

Answer:

The minimum surface area of the container is 276.791 square units.

Step-by-step explanation:

Let be A(r) = \pi\cdot r^{2} + \frac{1000}{r}, \forall \,r \in \mathbb{R}, r \geq 0. The first and second derivatives of such function are, respectively:

First derivative

A'(r) = 2\cdot \pi \cdot r -\frac{1000}{r^{2}}

Second derivative

A''(r) = 2\cdot \pi +\frac{2000}{r^{3}}

The critical values of r are determined by equalizing first derivative to zero and solving it: (First Derivative Test)

2\cdot \pi \cdot r -\frac{1000}{r^{2}} = 0

2\cdot \pi \cdot  r^{3} - 1000 = 0

r = \sqrt[3]{\frac{1000}{2\pi} }

r \approx 5.419 (since radius is a positive variable)

To determine if critical value leads to an absolute minimum, this input must be checked in the second derivative expression: (r \approx 5.419)

A''(5.419) = 2 + \frac{2000}{5.419^{3}}

A''(5.419) = 14.568

The critical value leads to an absolute minimum, since value of the second derivative is positive.

Finally, the minimum surface area of the container is:

A(5.419) = \pi\cdot (5.419)^{2} + \frac{1000}{5.419}

A(5.419) \approx 276.791

The minimum surface area of the container is 276.791 square units.

7 0
3 years ago
Help please! The area of a swimming pool is 45 square meters. The width of the pool is 3 meters. What is the length of the pool
denis-greek [22]

Answer: 15 m

Step-by-step explanation:

Given

The area of the swimming pool is A=45\ m^2

Width of the pool is w=3\ m

Suppose l is the length of the pool

So, the area is given by the multiplication of length and width

\Rightarrow A=lw\\\Rightarrow 45=3l\\\Rightarrow l=15\ m

So, the length of the pool is 15 m.

8 0
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