Help pls I need help pls

Find the general solution of the given system. Use a computer system or graphing calculator to construct a direction field and t

zloy xaker [14]

Answer:

hello your question is incomplete attached below is the complete question and solution

answer : general solution ( X ) = $C_{1} e^{3t} \left \{ {{1} \atop {-1}} \right. + C_{2} e^{3t} \left \{ {{1} \atop {-1}} \right.$

Step-by-step explanation:

attached below is the detailed solution to determine the general solution of the given system

general solution ( X ) = $C_{1} e^{3t} \left \{ {{1} \atop {-1}} \right. + C_{2} e^{3t} \left \{ {{1} \atop {-1}} \right.$

7 0

3 years ago

Find the volume of the rectangular prism , in cubic centimeters please answer

12345 [234]

Answer:

the volume of the rectangular prism = 166.336 cubic cm

Hence, option C is correct.

Step-by-step explanation:

We can determine the volume of the rectangular prism using the formula given below.

The volume of the rectangular prism = Base area x Height

<u><em>Determining the Base area:</em></u>

Given

Length l = 3.2 cm

Width w = 4.6 cm

Area of the Base area = l × w

= 3.2 × 4.6

= 14.72 cm²

Thus, the area of the Base area = 14.72 cm²

As the height h = 11.3 cm

Thus,

The volume of the rectangular prism = Base area x Height

= 14.72 x 11.3

= 166.336 cubic cm

Therefore, the volume of the rectangular prism = 166.336 cubic cm

Hence, option C is correct.

8 0

2 years ago

A recursive rule for a geometric sequence is

LuckyWell [14K]

Answer:

C. $a_n=(9)(\frac{2}{3})^{n-1}$

Step-by-step explanation:

Iterative geometric sequence:

$a_n=a_1x^{n-1}$

Recursive geometric sequence:

$a_n=xa_{n-1}$

The equations are very similar and you only really need to rearrange it. The factor (2/3) and the first term (9) are given, so you can write the iterative equation:

$a_n=(9)(\frac{2}{3})^{n-1}$

And so the answer is C.

5 0

2 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago

Can anybody help? Exponential Functions

lana [24]

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4 0

3 years ago