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2 years ago

If r = 9 units and x = 5 units, then what is the volume of the cylinder

Mathematics

1 answer:

GuDViN [60]2 years ago

5 0

Answer:

The answer is volume= 1272

Step-by-step explanation:

volume of a cylinder= pi (3.14)*r^2*h

3.14*9^2*5, 3.14*81*5= 1271.7 when rounded is 1272

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Factorise completely 2y^2-4y

Serga [27]

To factor an expression, first you have to find the GCF or Greatest Common Factor of all of the pieces of the expression.

The GCF of 2y^2 and -4y is 2y

So, to factor this expression, we need to divide all of the pieces of the expression by the GCF.

2y(y-2)

2y^2 - 4y in completely factored form is 2y(y-2)

8 0

3 years ago

Read 2 more answers

A farmer owns a 100 acre farm and plans to plant at most three crops. The seed for crops A,B, and C costs $40, $20, and $30 per

aev [14]

Answer:

The number of acre per crop for maximum profit is;

Crop A = 0 acres

Crop B = 60 acres

Crop C = 40 acres

Profit, P = $26,000

Step-by-step explanation:

We plant A in X acres

B in Y acres and

C in Z acres

Therefore, X + Y + Z ≤ 100

we work A for 1·X workdays

B for 2·Y workdays and

C for 1·Z workdays

Where X + 2·Y + Z ≤ 160

$40·X for crop A

$20·Y for crop B and

$30·Z for crop C is spent whereby

$40·X + $20·Y + $30·Z ≤ $3200

The farmer makes

$100·X from crop A

$300·Y from crop B and

$200·Z from crop C

P = $100·X + $300·Y + $200·Z

Therefore, we have three equations with three unknowns solving the equations simultaneously, we have

X + Y + Z = 100....................................................(1)

X + 2·Y + Z = 160.................................................(2)

$40·X + $20·Y + $30·Z = $3200....................(3)

By subtracting equation (1) from (2) gives Y = 60 acres

Multiplying equation (1) by 40 and subtracting from (3) we have Z = -40

and therefore, Y = 80

If he plants only B the farmer has 2 work day per acre and since there is a max of 160 days, he can only plant on 80 acres, therefore, total profit = $300 × 80 = $24,000

Comparing the profit per acre to the seed cost we have Profit for seed A = $100 while cost = $40 per acre,

If we remove seed A we have

Y + Z = 100....................................................(4)

2·Y + Z = 160.................................................(5)

$40·X + $20·Y + $30·Z = $3200....................(3)

Solving equation (4) and (5), we have Y = 60 acres and Z = 40 acres

Therefore, the profit becomes

$300 × 60 + $200 × 40 = $26,000.

3 0

2 years ago

Help Solve 10 12 − 3 8 . Show your solution as an equation.

ozzi

Say what now I hadn’t learned that yet omg I’m sry

8 0

2 years ago

The area of one field is 16 acres, and the area of the second field is 1 1/4 times bigger. A barn of wheat on the first field ma

gregori [183]

Answer: 23.89 thousands of pounds is more wheat that was gathered from the second field than from the first field.

Step-by-step explanation:

Since we have given that

the area of one field = 16 acres

Area of second field is given by

$1\frac{1}{4}\times 16\\\\=\frac{5}{4}\times 16\\\\=5\times 4\\\\=20\ acres$

A barn of wheat on the first field makes up

$3\frac{7}{12}\times 16\\\\=\frac{43}{12}\times 16\\\\=57.33\text{ thousands of pounds.}$

A barn of wheat on the second field makes up

$1\frac{2}{15}\times 20\\\\=\frac{43}{12}\times \frac{17}{15}\times 20\\\\=81.22\text{ thousands of pounds }$

Now,

$81.22-57.33=23.89$

Hence, 23.89 thousands of pounds is more wheat that was gathered from the second field than from the first field.

7 0

3 years ago

Dividing Polynomials with Tables Isiah is dividing 2x3 - x2 + 2x + 5 by x + 1 using a division table. His work is shown here. Wh

lukranit [14]

Answer:

Step-by-step explanation:

We are asked to find the value of A. We know from the question that we need to have the sum of -3x and (A)x equal the third term of the original polynomial, which is 2x. written out in an equation, it looks like this.

$-3x+(A)x=2x$

We can simplify the equation if we add 3x to both sides, which then leaves us with this.

$(A)x=5x$

We can further simplify the equation by dividing both sides by x. This leaves us with our last equation for this problem.

$A=5$

Finally, we have our answer. We can also verify that this is a valid integer by multiplying our, now completed, quotient by the divisor and adding the remainder, which in this case, our remainder is 0, so we will not be including it in our operation.

$(x+1)(2x^{2}-3x+5)$

If our calculations were all correct, the product of these polynomials should equal our dividend, verifying our integer is valid; lo' and behold, it is.

$2x^{3}-x^{2}+2x+5$

8 0

2 years ago