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DanielleElmas [232]
3 years ago
15

The population of deer in a certain national park can be approximated by the function P(x)=150(1.07)^x, where x is the number of

years since 1995. In which year will the population reach 300? Hint: an answer such as 2002.4 would represent the year 2002.
A.2026
B.2005
C.2038
D.2016
Mathematics
2 answers:
SVEN [57.7K]3 years ago
6 0

Answer:

B. 2005

Step-by-step explanation:

We have been given that population of deer in a certain national park can be approximated by the function P(x)=150(1.07)^x, where x is the number of years since 1995. We are asked to find the year in which population will reach 300.

To solve our given problem, we will equate P(x)=300 and solve for x as:

300=150(1.07)^x

\frac{300}{150}=\frac{150(1.07)^x}{150}

2=(1.07)^x

Now, we will take natural log on both sides as:

\text{ln}(2)=\text{ln}((1.07)^x)

\text{ln}(2)=x\text{ln}(1.07)

x=\frac{\text{ln}(2)}{\text{ln}(1.07)}

x=10.2447

x\approx 10

Now, we will find 10 years after 1995 that is 1995+10=2005.

Therefore, the population will be 300 in year 2005 and option B is the correct choice.

Oliga [24]3 years ago
3 0

Answer:

b. 2005

Step-by-step explanation:

(apex)

300=150(1.07)^x

1.07^x=2

x=ln 2/ln 1.07

=10.24

1995 plus ten years = 2005

hope this helps

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