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Gwar [14]
3 years ago
10

Can you guys help me and show your work

Mathematics
1 answer:
devlian [24]3 years ago
3 0
(1) 19.4 (2) 34.2 (3) 298.4

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A function is represented by these ordered pairs.
Crazy boy [7]

answer: 4

Step-by-step explanation:

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4 years ago
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Find the value of the expression 63 - 21 + (3 x 11)
bixtya [17]

Answer: First solve the parentheses using order of operations. Then add and subtract from left to right.

Demo:

(3 * 11) = 33

Equation now looks like:

63 - 21 + 33

63 - 21 = 42

Equation now looks like:

42 + 33

42 + 33 = 75

The value of this expression is 75.

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Mary sold 20 tacos and
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4 years ago
Find the equation of the parallel to the line 3x-2y=5 and passing through the midpoint of the line segment joining the points (-
levacccp [35]

Given:

The equation of parallel line is:

3x-2y=5

The required line passing through the midpoint of the line segment joining the points (-4,2) and (2,4).​

To find:

The equation of required line.

Solution:

Midpoint of  line segment joining the points (-4,2) and (2,4) is:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Midpoint=\left(\dfrac{-4+2}{2},\dfrac{2+4}{2}\right)

Midpoint=\left(\dfrac{-2}{2},\dfrac{6}{2}\right)

Midpoint=\left(-1,3\right)

It means the required line passes through the point (-1,3).

The slope of line Ax+By=C is:

m=\dfrac{-A}{B}

The given equation is:

3x-2y=5

Here, A=3 and B=-2. So, the slope of the line is:

m=\dfrac{-3}{-2}

m=1.5

Slope of parallel lines are same. So, the slope of the required line is 1.5.

The required line passes through the point (-1,3) with slope 1.5. So, the equation of the line is:

y-y_1=m(x-x_1)

y-3=1.5(x-(-1))

y-3=1.5(x+1)

y-3=1.5x+1.5

Adding 3 on both sides, we get

y=1.5x+1.5+3

y=1.5x+4.5

Therefore, the equation of the required line is y=1.5x+4.5.

8 0
3 years ago
Simplify 8 - (-5) - 4(-7).<br><br> -63<br> -15<br> 41<br> 68
jekas [21]
The correct answer is 41.
3 0
3 years ago
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