You have 28 meters of fence to make 3 sides.
28/3 = 9.3333
The pen will be 9.3333 by 9.3333 meters
Answer:
The probability is 
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8,
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function
with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is

Answer:
The answer is $150
Step-by-step explanation:
hope that helps
Solutions: $100x.50=50
$100+$50= $150
If you think about it, an octagon is made up of 8 triangles. So you first find the area of one triangle then multiply it by 8 for the total area:
A=1/2bh
A=1/2(9.9)(12)
A=59.4
59.4 x 8= 475.2
Therefore the total area for the octagon should be 475.2 units^2
Hope this helps !