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Alex787 [66]
3 years ago
10

Which equation has the solutions x = 1+

Mathematics
1 answer:
BaLLatris [955]3 years ago
5 0

Answer:

The last equation x2 - 2x -4 = 0

has solution  (x - 1)^2 - 5 = 0,   x  =  1 + root(5)  or  x = 1 - root(5)

Step-by-step explanation:

If a quadratic function has roots 1 and 5

f(x) = (x -1)(x- 5)

f(x) = x^2 - 6x + 5

Unless you meant.  -4 and 6  ?

g(x) = (x + 4)(x - 6)

g(x) = x^2 -2x -24

-------------------------

Or did you mean  x = 1 and x =4 ?...

x^2 + 2x + 4 = 0  :   complete square  x^2 + 2x + 1 + 3 = 0,   (x+1)^2 + 3 = 0

x^2 - 2x + 4 = 0 :  complete square:  (x -1)^2 + 3 = 0

0x^2 + 2x - 4 = 0,    2x - 4 = 0,  x = 2

x^2 - 2x - 4 = 0  becomes:   x^2 - 2x + 1 - 1 -4 = 0 ;  (x - 1)^2 - 5 = 0

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The mayor is interested in finding a 98% confidence interval for the mean number of pounds of trash per person per week that is
saul85 [17]

Solution :

Given :

Sample mean, $\overline X = 34.2$

Sample size, n = 129

Sample standard deviation, s = 8.2

a. Since the population standard deviation is unknown, therefore, we use the t-distribution.

b. Now for 95% confidence level,

   α = 0.05, α/2 = 0.025

  From the t tables, T.INV.2T(α, degree of freedom), we find the t value as

  t =T.INV.2T(0.05, 128) = 2.34

  Taking the positive value of t, we get  

  Confidence interval is ,

  $\overline X \pm t \times \frac{s}{\sqrt n}$

 $34.2 \pm 2.34 \times \frac{8.2}{\sqrt {129}}$

 (32.52, 35.8)

 95% confidence interval is  (32.52, 35.8)

So with $95 \%$ confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.

c. About $95 \%$ of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about $5 \%$ that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.  

4 0
3 years ago
Helpppppp me plssssss
MaRussiya [10]

I have solved the answer in the pic below, hope it helpss!!!!

8 0
3 years ago
In how many ways can we rearrange the digits in the number 12321? With formula and not just listing the numbers.
Archy [21]

Answer:

With a 5-digit number, you have 5 choices for the first digit. There will be 4 digits left so you have 4 choices for the second digit. After you have chosen the first 2 digits there will be 3 remaining so you will have 3 choices for the third digit. Hence there are 2 choices for the fourth digit and only 1 choice for the fifth digit. Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 2 and 1

7 0
3 years ago
Please help me out..
sdas [7]

Answer:

x=41

y=139

Step-by-step explanation:

x+y = 180  since they form a straight line

y is 3x +16

y = 3x +16

Replace y in the first equation

x+3x +16 = 180

Combine like terms

4x +16 = 180

Subtract 16 from each side

4x+16-16 =180-16

4x =164

Divide each side by 4

4x/4 =164/4

x = 41

y = 3x +16

y = 3*41 +16 = 123+16 =139

5 0
3 years ago
Help please and this time please put an explanation just don't only say the answer <br> thank you
coldgirl [10]

✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽

➷ T\boxed{4} B\boxed{24}

✽ Ok, so B is the number of boys and T is the number of teachers.

➷ t \div ( B + 18) = \frac{2}{21}

\frac{B}{18} = \frac{4}{3}

✽ Then solve the second equation for B.

➷ B = 24

✽ Plug into the first equation to find T.

➷ T \div (24 + 18) = \frac{2}{21}

T = 4

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ May ♡

5 0
3 years ago
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