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3 years ago

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A caterer charges a setup fee of $50, plus $20 per person. How much will the caterer charge if 35 people attend the party?

1 answer:

Oduvanchick [21]3 years ago

5 0

750 dollars all you have to do is multiply 20 and 35 which gets you too 700 and now you add 50 and you get your answer 750 dollars

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Twelve runners are competing in a race. In how many different ways can the first,second,and third place trophies be awarded

zubka84 [21]

Since only one person can finish in first place, one in second, etc., the total number of placers is 12x11x10, or 1320 different ways the 12 racers can finish 1st, 2nd and 3rd....
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3 years ago

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Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (

natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

$I=\int\limits^{}_{} \int\limits^{}_D {x*y} \, dA = \int\limits^{}_{} \int\limits^{}_D {x*y} \, dx*dy$

since D is the rectangle such that 0<x<3 , 0<y<3

$I=\int\limits^{}_{} \int\limits^{}_D {x*y} \, dA = \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y} \, dx*dy = \int\limits^{3}_{0} {x} \, dx\int\limits^{3}_{0} {y} \, dy = x^{2} /2*y^{2} /2 = (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4$

4 0

3 years ago

What is the lateral area of the square pyramid, to the nearest whole number?

emmainna [20.7K]

Answer:AL=aa2+4h2

Step-by-step explanation:

8 0

3 years ago

ABC is an isosceles triangle in which AC =BC.

aev [14]

Given:

ABC is an isosceles triangle in which AC =BC.

D and E are points on BC and AC such that CE=CD.

To prove:

Triangle ACD and BCE are congruent.

Solution:

In triangle ACD and BCE,

$AC=BC$ (Given)

$AC\cong BC$

$\angle C\cong m\angle C$ (Common angle)

$CD=CE$ (Given)

$CD\cong CE$

In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.

$\Delta ACD\cong \Delta BCE$ (SAS congruence postulate)

Hence proved.

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3 years ago

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In a tutoring session, 2/3 of an hour was spent reviewing math problems. Adelina attended 3/4 of the tutoring session. How much

fgiga [73]

Answer:

Time spend by Adelina at the tutoring session is 30 minutes.

Step-by-step explanation:

Given : In a tutoring session, $\frac{2}{3}$ of an hour was spent reviewing math problems and Adelina attended $\frac{3}{4}$ of the tutoring session.

We have to find the time Adelina spend at the tutoring session.

We know, 1 hour = 60 minutes.

Total time taken in tutoring session = $\frac{2}{3}\times 60=40$ minutes.

also, Adelina attended $\frac{3}{4}$ of the tutoring session that is $\frac{3}{4}$ of 40 minutes.

that is $\frac{3}{4}\times 40=30$ minutes.

Thus, time spend by Adelina at the tutoring session is 30 minutes.

4 0

3 years ago