The rewritten form of the expression given in the task content in which case, the properties of the logarithm are used is; log2(z³/y²) + log9(y⁴x¹²).
<h3>What is the equivalent expression to the logarithmic expression given in the task content?</h3>
It follows from the task content that the logarithmic expression given in the task content is;
log2z + 2log2z + 4log9y + 12log9x - 2log2y
In which case, all terms are to their respective logarithmic bases.
Hence, it follows that; we have;
log2z³ - log2y² + log9y⁴ + log9x¹²
= log2(z³/y²) + log9(y⁴x¹²)
Read more on logarithm laws;
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Answer:
40
Step-by-step explanation:
(2x+1/(2x))^5 *(2x -1/(2x))^5
= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2
= (4x^2-1/4(x)^2)^5
now
x =4x^2. ,a = 1/4(x)^2 ,n =5
we have
general term = Cr *x^r *a^(n-r)
= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)
= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)
= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)
= Cr * 4(2r-n) *x(4r-2n)
now for x^2
4r-2n = 2
4r -10=2
4r =12
r = 3
now for coeff
C(5,3) * 4^(2*3-5)
5!/(3!*(5-3)!) * 4
5*4/(2*1)*4
40
Answer:
9 gallons of water per minute
Step-by-step explanation:
First identify what you know:
1) The pipe was flowing water for eight minutes.
2) In that eight minutes, 72 gallons of water came out.
So, if 72 gallons of water came out in eight minutes, how many gallons flowed out in a single minute? Well, assuming that the flow rate was consistent, then simply divide the total number of gallons that flowed out, by the number of minutes the pipe was open!
72/8 = 9
The pipe released 9 gallons of water per minute, thus resulting in 72 gallons of water in 8 minutes!
Hope this helps! :)
<u>Answer:</u>
C
it's the set that will add to 180°
36° + 42° + 102° = 180°
To find the surface area of a rectangular prism or cube, you would do height*width*2+height*length*2+length*width*2.
