Answer:
- 0.8
Step-by-step explanation:
The first thing we want to do here is simplify the expression -
( 2x + 5 ) - 2x, Distribute the "
" to elements within the parenthesis
=
2x +
5 - 2x, Focus on simplifying the expression "
2x +
5 "
=
- 2x
=
- 2x, Combine fractions
=
+ 3
=
x + 3
So we have our simplified expression "
x + 3, " with
being the coefficient of x. Our requirements are that this fraction should be expressed as a decimal, so we can simply divide the numerator by the denominator to figure that out,
- 4 / 5 = - 0.8,
Solution = - 0.8
Answer:
-6-b
Step-by-step explanation:
4(1-2b)+7b-10
Multiply what's in parantheses
4(1)=4
4(-2b)=-8b
4-8b+7b-10
Combine like terms
4-10 -8b+7b
-6-b
Hope this helps :)
74,233 increased by 58,490 is 74,233 * 58,490 so its 4,341,888, 170. So 4 billion, 341 million, 888 thousand, 170.
Scientific notation is 4.34188817 * 10 to the 9th power.
Answer:
(a) 
The expected number in the sample that treats hazardous waste on-site is 0.383.
(b) 
There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Step-by-step explanation:
Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.
N = 209
Only eight of these facilities treated hazardous waste on-site.
r = 8
a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?
n = 10
The expected number in the sample that treats hazardous waste on-site is given by




Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.
b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site
The probability is given by
For the given case, we have
N = 209
n = 10
r = 8
x = 4




Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.