Answer:
sin 3 θ = 3 sin θ - 4 sin³θ
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given sin 3 θ
= sin ( 2θ + θ )
apply trigonometric formula
<em> sin ( A + B) = sin A cos B + cos A sin B </em>
<em> sin 2 A = 2 sin A cos B</em>
<em> Cos 2 A = 1 - 2 sin² A </em>
<em> cos ² A - sin ² A = 1</em>
<u><em>Step(ii):</em></u>-
sin 3 θ = sin ( 2θ + θ )
= sin 2θ cosθ + cos2θ sin θ
= 2 sin θ cos θ cos θ +( 1 - 2 sin² θ )sin θ
= 2 sin θ (cos² θ ) + sin θ- 2 sin³ θ
= 2 sin θ ( 1- sin²θ) + sin θ- 2 sin³ θ
= 2 sin θ - 2sin³θ + sin θ- 2 sin³ θ
= 3 sin θ - 4 sin³θ
<u><em>Final answer</em></u> :-
sin 3 θ = 3 sin θ - 4 sin³θ
Answer:
9526/87
Step-by-step explanation:
87·x=9,526
x=9526/87
Answer:
71, 72, 73
Step-by-step explanation:
So we want to find three consecutive integers that equal 216.
Let the first integer be n.
Then the second integer is n+1, and the third integer is n+2.
Thus:
Combine like terms:
Subtract 3 from both sides:
Divide 3 from both sides:
So, the first term is 71.
And the other two is 72 and 73.
And we are done :)
Answer:
Step-by-step explanation:
What are you looking for?
Answer:
7/9+1/6+2/3+6/18=28/36+6/36+24/36+12/36
=70/36
=1/34/36
