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AlekseyPX
3 years ago
15

Pls help me for once....

Mathematics
1 answer:
ryzh [129]3 years ago
3 0
The answers are C and also D
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Suppose you average 82 on your first 7 test. What must you score on the eighth test to raise your average to 84?
natima [27]

so hmmm on average on the last 7 test, you get 82, so hmmm we could say that on each of the 7 tests you got 82, so you got 82, 7 times.

now, let's say in the 8th test, you get a grade of "g", now, if we were to get an average of all 8 tests, that means the average will simply be (82*7) + "g", and we know that's 84, so

\cfrac{(\stackrel{\textit{sum of all first seven tests}}{82+82+82+82+82+82+82})~~ + ~~g}{8}~~ = ~~84\implies \cfrac{(82\cdot 7)~~ + ~~g}{8}~~ = ~~84 \\\\\\ \cfrac{574+g}{8}=84\implies 574+g=672\implies g=672-574\implies g=98

7 0
1 year ago
Read 2 more answers
Help me please urgent !!
Andre45 [30]

Answer:

0

Step-by-step explanation:

-0.75-20+71/2+13.25

-0.75-20+15/2+13.25

-7.5+15/2

-15/2+15/2

=0

7 0
3 years ago
Read 2 more answers
Two systems of equations are shown below: System A System B 3x + 2y = 3 −x − 14y = 1 −2x − 8y = −1 −2x − 8y = −1 Which of the fo
Sauron [17]

The two linear equations represented in system A as :

3 x + 2 y =3   -------(1)

- 2 x - 8 y = -1  ------(2)

(1) × 2 + (2) × 3 gives

⇒ 6 x + 4 y - 6 x - 24 y = 6 -3

⇒ - 20 y = 3

⇒ y = \frac{-3}{20}

Putting the value of y in equation (1), we get

3 x  - \frac{6}{20}=3\\\\ 3 x= \frac{66}{20} \\\\ x=\frac{11}{10}

Two linear equation represented in system B is:

3.   -x - 14 y =1

4.   - 2 x - 8 y = -1

-2 ×Equation (3) + Equation (4)=

2 x +28 y- 2 x - 8 y= -2 -1

⇒ 20 y = -3

⇒y =\frac{-3}{20}

Putting the value of y in equation (3),we get

-x + \frac{42}{20}=1 \\\\ x=\frac{22}{20}=\frac{11}{10}

As Two system , that is system (A) and System (B) has same solution.

By looking at all the options , i found that Option (D) is correct. The two system will have the same solution because the first equation of System B is obtained by adding the first equation of System A to 2 times the second equation of System A.

6 0
3 years ago
Read 2 more answers
Plzz help steps if possible if not its ok j=i just need to pass this class
hammer [34]

Answer:

\text{(B) }\cos 40^{\circ}=\frac{x}{60}

Step-by-step explanation:

In any triangle, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse (longest side) of the triangle. (a/h)

The angle marked 40 degrees has an adjacent side of x and the hypotenuse of the triangle is 60.

Therefore, we have the equation:

\boxed{\cos 40^{\circ}=\frac{x}{60}}

6 0
3 years ago
Subtract 7 pounds 3 ounces from 10 pounds
butalik [34]
(10 pounds) - (7 pounds 3 ounces) =
2.8125 pounds
7 0
2 years ago
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