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AlekseyPX
3 years ago
15

Pls help me for once....

Mathematics
1 answer:
ryzh [129]3 years ago
3 0
The answers are C and also D
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In a random sample of cars driven at low altitudes, of them exceeded a standard of grams of particulate pollution per gallon of
Orlov [11]

Complete question is;

In a random sample of 370 cars driven at low altitudes, 43 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed. In an independent random sample of 80 cars driven at high altitudes, 23 of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard at an level of significance? Group of answer choices

Answer:

Yes we can conclude that there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard (P-value = 0.00005).

Step-by-step explanation:

This is a hypothesis test for the difference between the proportions.

The claim is that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

Then, the null and alternative hypothesis are:

H0 ; π1 - π2 = 0

H1 ; π1 - π2 < 0

The significance level would be established in 0.01.

The random sample 1 (low altitudes), of size n1 = 370 has a proportion of;

p1 = x1/n1

p1 = 43/370

p1 = 0.116

The random sample 2 (high altitudes), of size n2 = 80 has a proportion of;

p2 = x2/n2

p2 = 23/80

p2 = 0.288

The difference between proportions is pd = (p1-p2);

pd = p1 - p2 = 0.116 - 0.288

pd = -0.171

The pooled proportion, we need to calculate the standard error, is:

p = (x1 + x2)/(n1 + n2)

p = (43 + 23)/(370 + 80)

p = 66/450

p = 0.147

The estimated standard error of the difference between means is computed using the formula:

S_(p1-p2) = √[((p(1 - p)/n1) + ((p(1 - p)/n2)]

1 - p = 1 - 0.147 = 0.853

Thus;

S_(p1-p2) = √[((0.147 × 0.853)/370) + ((0.147 × 0.853)/80)]

S_(p1-p2) = 0.044

Now, we can use the formula for z-statistics as;

z = (pd - (π1 - π2))/S_(p1-p2)

z = (-0.171 - 0)/0.044

z = -3.89

Using z-distribution table, we have the p-value = 0.00005

Since the P-value of (0.00005) is smaller than the significance level (0.01), then the effect is significant.

We conclude that The null hypothesis is rejected.

Thus, there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

6 0
3 years ago
If ∆ABC congruent ∆DEF, which of the following can you NOT conclude as being true?
enyata [817]

Answer:

I believe the answer would be C (sorry i messed uo the first time)

4 0
3 years ago
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FinnZ [79.3K]

Answer:

it is the  last one give me 5 stars  thanks

Step-by-step explanation:

5 0
3 years ago
On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases from quadrant 2 into quadrant 1. It
dusya [7]

Answer:

f(x) = 2^{(3x)}

Step-by-step explanation:

The given options are,

a) f(x) = 2^{(3x)}

b) f(x) = ({\frac {1}{2}})^{3x}

c) f(x) = 2 \times ({\frac {1}{3}})^{x}

d) f(x) = \frac {1}{2} \times ({\frac {1}{3}})^{x}

Now, among the given options only option (a) satisfies the criteria stated in the question i. e.,

     1. f(x) → 0 as x → - ∞  and

     2 f(0) = 1

so, the correct answer is,

f(x) = 2^{(3x)}

7 0
3 years ago
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A youth group is setting up camp. Rain is predicted, so the campers decide to build a fly, or rain cover, over their tent. The f
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The image for this is attached for reference. This problem can be used by the Pythagorean equation.  To make solving convenient, let us see only one part of the tent. Hence, one side is half of the tend width which is 16/2ft. Height is 12 ft. The unknown side is the hypotenuse. The answer is: 
a^{2} + b^{2}  = c^{2}    8^{2} + 12^{2}  = c^{2}   c = 14.4

7 0
3 years ago
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