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user100 [1]
3 years ago
7

Which of the following is a factor of 7x2 - 12x - 4? (6 points)

Mathematics
1 answer:
grin007 [14]3 years ago
4 0

Answer:

We conclude that 'None of the above' is the correct answer.                    

Step-by-step explanation:

Given the expression

7x^2\:-\:12x\:-\:4

Breaking the expression into groups

7x^2\:-\:12x\:-\:4=\left(7x^2+2x\right)+\left(-14x-4\right)

Factor out x from 7x^2\:+\:2x

=x\left(7x+2\right)

Factor out -2 from \left(-14x-4\right)

=-2\left(7x+2\right)

so the expression becomes

7x^2\:-\:12x\:-\:4=\left(7x^2+2x\right)+\left(-14x-4\right)

                         =x\left(7x+2\right)-2\left(7x+2\right)

Factor out the common term 7x+2

                         =\left(7x+2\right)\left(x-2\right)

Therefore, from the given options, we conclude that 'None of the above' is the correct answer.                    

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Joe bought 16 pounds of flour for $7.<br> How many pounds of flour did he get per dollar?
wolverine [178]

Answer:

112

Step-by-step explanation:

7 0
3 years ago
Mc Donald’s sells about 150 hamburgers every 3 seconds. How many seconds will it take to sell 6,400 hamburgers?
Strike441 [17]
150/3=50
6400/50=128
So 128 seconds
3 0
3 years ago
(-6ab-7a+2) - (-2ab+8)<br> Helpppp
Alika [10]

Answer:-4ab-7a-6

Step-by-step explanation:

(-6ab-7a+2) - (-2ab+8)

-6ab -7a + 2 + 2ab-8 (removed parentheses & fixed the negative at the end)

-4ab-7a-6 (combined like terms)

5 0
3 years ago
Beth spent $53 on 3 hostas and 5 pots of ivy. Stefan spent $39 on 1 hosts and 7 pots of ivy. How much does one hosta and one pot
vichka [17]

Cost of one hosta is $11 and one pot of ivy is $4.

Step-by-step explanation:

Let,

Cost of one hosta = x

Cost of one pot of ivy = y

According to given statement;

3x+5y=53     Eqn 1

x+7y=39       Eqn 2

Multiplying Eqn 2 by 3

3(x+7y=39)\\3x+21y=117\ \ \ Eqn\ 3

Subtracting Eqn 1 from Eqn 3

(3x+21y)-(3x+5y)=117-53\\3x+21y-3x-5y=64\\16y=64

Dividing both sides by 16

\frac{16y}{16}=\frac{64}{16}\\y=4

Putting y=4 in Eqn 2

x+7(4)=39\\x+28=39\\x=39-28\\x=11

Cost of one hosta is $11 and one pot of ivy is $4.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/9533500
  • brainly.com/question/9527632

#LearnwithBrainly

6 0
3 years ago
Part A: The average rate of change between the 2nd and 3rd point is Select a Value Part A: The average rate of change between th
Fofino [41]

Answer:

Rate = 6

Rate = 10

Rate = 18

Rate = 162

Step-by-step explanation:

Given

See attachment for table

Solving (a): Rate of change between 2nd and 3rd point on A

The rate of change is calculated as:

Rate = \frac{y_2 - y_1}{x_2 - x_1}

In table A, the 2nd and 3rd point is:

(x_1,y_1) =(1,7)

(x_2,y_2) =(2,13)

So, the average rate of change is:

Rate = \frac{13 - 7}{2 - 1}

Rate = \frac{6}{1}

Rate = 6

Solving (b): Rate of change between 3rd and 4th point on A

In table A, the 3rd and 4th point is:

(x_1,y_1) =(2,13)

(x_2,y_2) =(3,23)

So, the average rate of change is:

Rate = \frac{23 - 13}{3 - 2}

Rate = \frac{10}{1}

Rate = 10

Solving (c): Rate of change between 2nd and 3rd point on B

In table B, the 2nd and 3rd point is:

(x_1,y_1) =(2,11)

(x_2,y_2) =(3,29)

So, the average rate of change is:

Rate = \frac{29 - 11}{3 - 2}

Rate = \frac{18}{1}

Rate = 18

Solving (d): Rate of change between 4th and 5th point on B

In table B, the 4th and 5th point is:

(x_1,y_1) =(4,83)

(x_2,y_2) =(5,245)

So, the average rate of change is:

Rate = \frac{245 - 83}{5 - 4}

Rate = \frac{162}{1}

Rate = 162

7 0
3 years ago
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