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gulaghasi [49]
3 years ago
9

four friends contributed the sum of money to a charitable organization in the ratio 1:3:5:7. if the largest amount contrebuted i

s birr 35. calculate the total amount contributed by the four people​
Mathematics
1 answer:
suter [353]3 years ago
3 0

9514 1404 393

Answer:

  birr 80

Step-by-step explanation:

The total number of ratio units is 1+3+5+7 = 16. The largest amount is represented by 7 ratio units, so is 7/16 of the total. The total contributed is ...

  16/7 × (birr 35) = birr 80

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Tyler got 1/(18 +1) = 1/19 of the 1995 votes, so 1995/19 = 105 votes.
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Find the scale factor please.
torisob [31]

Answer:

5/2

Step-by-step explanation:

The scale factor for linear measures, such as perimeter, is the square root of the scale factor for areas. The ratio of larger area to smaller is ...

... 75/12 = 25/4

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... √(25/4) = 5/2


3 0
4 years ago
Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe
ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for n\geq 78

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: \sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4

For n=1: \sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4

From this point we will assume that n\geq 2

As we can see, \sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4 and (4n)^4=256n^4. Then,

\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4

Now, we will use the formula for the sum of the first 4th powers:

\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}

Therefore:

\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0

and, because n \geq 0,

465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1

Observe that, because n \geq 2 and is an integer,

n^2(465n-6n^2-10)\geq -1 \iff 465n-6n^2-10 \geq 0 \iff n(465-6n) \geq 10\\\iff 465-6n \geq 0 \iff n \leq \frac{465}{6}=\frac{155}{2}=77.5

In concusion, the statement is true if and only if n is a non negative integer such that n\leq 77

So, 78 is the smallest value of n that does not satisfy the inequality.

Note: If you compute  (4n)^4- \sum^{n}_{i=0} (2i)^4 for 77 and 78 you will obtain:

(4n)^4- \sum^{n}_{i=0} (2i)^4=53810064

(4n)^4- \sum^{n}_{i=0} (2i)^4=-61754992

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Kazeer [188]

Answer:

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Step-by-step explanation:

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A recipe for lemon bars uses 1 sticks of
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4 sticks of butter to make 4 batches of lemon bars
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