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2 years ago

Can someone please tell me if I found all the slopes of these coordinates correctly??

Mathematics

1 answer:

Alisiya [41]2 years ago

6 0

Answer:

yes I believe you have everything correct

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A new radar device is being considered for a certain missile defense system. The system is checked by experimenting with aircraf

adell [148]

Answer:

There is significant difference between the proportions of group A and group B.

Step-by-step explanation:

In this question we need to perform an hypothesis test on the difference of proportions (Δπ) and determine if there is any significant difference between the two proportions.

The null and alternative hypothesis are:

$H_0: \Delta \pi=0\\\\H_1: \Delta \pi\neq0$

The proportion of group A is $p_1=63/100=0.630$ .

The proportion of group B is $p_2=59/125=0.472$ .

The weighted average of p (to calculate s) is:

$p=\frac{n_1*p_1+n_2*p_2}{n_1+n_2}=\frac{100*0.630+125*0.472}{100+125}=\frac{63+59}{100+125}=\frac{122}{225}=0.542$

The estimated standard deviation is:

$s=\sqrt{\frac{p(1-p)}{n_1}+\frac{p(1-p)}{n_2} } =\sqrt{\frac{0.542(1-0.542)}{100}+\frac{0.542(1-0.542)}{125}} =\sqrt{\frac{0.248}{100} +\frac{0.248}{125} } \\\\s=\sqrt{0.00447} =0.067$

Then we can calculate z as

$z=\frac{p_1-p_2}{s}=\frac{0.630-0.472}{0.067}=\frac{0.158}{0.067}=2.36$

The P-value for z=2.36 is 0.009, which is less that the significance level of 0.05. The effect is significant and the null hypothesis is rejected.

There is significant difference between the proportions of group A and group B.

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B10%7D%20%3D%20%20%5Cfrac%7B4%7D%7Ba-3%7D" id="TexFormula1" title=" \frac{2

Alexxandr [17]

Hello there!

$Let's \ first \ rearrange \ the \ equation! \\ \\ ( 2/10-(4/a-3)=0 ) \\ \\ we \ first \ simply \ simplify \ first \ \boxed{ \frac{4}{a} } \\ \\ \left[\begin{array}{ccc}\ \left[\begin{array}{ccc}\boxed{ \frac{2}{10}-( \frac{4}{a})-3)=0} \end{array}\right] \end{array}\right] \\ \\ We \ then \ subtract \ its \ whole \ numbers. \\ \\ \boxed{3= \frac{3}{1} = \frac{3*a}{a} } \\ \\$

$\Longrightarrow \left[\begin{array}{ccc}2/10-(4-3a)/a=\boxed{0}\end{array}\right] \\ \\ we \ then \ simplify \ \boxed{1/5 \\ \\ 1/5-(4-3a)/a=0} \\ \\ \\ \boxed{\boxed{ \frac{a-((4-3a)*5}{5a} = \frac{16a-20}{5a} }} \\ \\ we \ then \ pull \ out \ some \ like \ terms . \\ \\ 16a - 20 = 4 * (4a - 5) \\ \\ solve \ 4 = 0 \ ; solve \ 4a-5 = 0 . \\ \\ 

\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow$

$\boxed{TAKE \ NOTICE} \\ \\ \\ \boxed{\boxed{ Add \ 5 \ to \ both \ sides \ of \ the \ equation : \ 4a = 5 }} \\ \\ \\ \left[\begin{array}{ccc} \left[\begin{array}{ccc}Divide \ both \ sides \ of \ the \ equation \ by \4: \\
 a = 5/4 = 1.250 \end{array}\right] \end{array}\right] \\ \\ \\ \boxed{\boxed{Your \ correct \ answers}}... \\ \\ \\ \boxed{ a = 5/4 = 1.250}$

I hope this helps you Cher!

7 0

2 years ago

The sum of two numbers is 80.6. One of

goblinko [34]

X+y= 80.6
9x=y
Then x+9x=10x=80.6
X=8.06
Y=72.54

6 0

2 years ago

Evaluate for x = 3 and y = 4: x^-2y^2 / x^0y^3

luda_lava [24]

Answer:

the answer im getting is 8y^5x sorry if its wrong

Step-by-step explanation:

https://www.symbolab.com/solver/step-by-step/4%3Ax%5E%7B-%7D2y%5E%7B2%7D%2Fx%5E%7B0%7Dy%5E%7B3%7D?or=input

5 0

2 years ago

What is greater than 100 inches or 3 yards and one of the

Nutka1998 [239]

To compare units either of them have to change to be the same unit

either change inches to yards, or yards to inches.

1 yard is 36 inches, so
3 yards = 3 × 36 = 108 in

100 in < 108 in

3 yards is greater.

4 0

3 years ago

Read 2 more answers