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dangina [55]
3 years ago
9

}{10} = \frac{4}{a-3}" alt=" \frac{2}{10} = \frac{4}{a-3}" align="absmiddle" class="latex-formula">
Solve the proportion, then leave the fraction in a fraction as simplest form. Thanks! :)
Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0
Hello there!

Let's \ first \ rearrange \ the \ equation! \\ \\ (     2/10-(4/a-3)=0 ) \\ \\ we \ first \ simply \ simplify \ first \ \boxed{ \frac{4}{a} } \\ \\   \left[\begin{array}{ccc}\  \left[\begin{array}{ccc}\boxed{ \frac{2}{10}-( \frac{4}{a})-3)=0} \end{array}\right] \end{array}\right]  \\ \\ We \ then \ subtract \ its \ whole \ numbers. \\ \\ \boxed{3= \frac{3}{1} = \frac{3*a}{a} } \\ \\

\Longrightarrow   \left[\begin{array}{ccc}2/10-(4-3a)/a=\boxed{0}\end{array}\right]  \\ \\ we \ then \ simplify \ \boxed{1/5 \\ \\ 1/5-(4-3a)/a=0} \\ \\ \\ \boxed{\boxed{ \frac{a-((4-3a)*5}{5a} = \frac{16a-20}{5a} }} \\ \\  we \ then \ pull \ out \ some \ like \ terms . \\ \\   16a - 20  =   4 * (4a - 5) \\ \\  solve \  4   =  0 \ ; solve \ 4a-5 = 0 . \\ \\ 

\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow

\boxed{TAKE \ NOTICE} \\ \\ \\ \boxed{\boxed{ Add \  5  \ to \ both \ sides \ of  \ the \ equation : \   4a = 5 }} \\ \\ \\   \left[\begin{array}{ccc}  \left[\begin{array}{ccc}Divide  \ both \ sides \ of \ the \ equation \ by  \4: \\
                     a = 5/4 = 1.250 \end{array}\right] \end{array}\right]  \\ \\ \\ \boxed{\boxed{Your \ correct \ answers}}... \\ \\ \\ \boxed{  a = 5/4 = 1.250}

I hope this helps you Cher! 
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I don't think you're stupid. ^^
Let's take the third term, 8. If n=3, then an should be 8.
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