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3 years ago

What is the measure of angle M? Type only the number:

Mathematics

1 answer:

Aleks04 [339]3 years ago

4 0

Answer: 30

Step-by-step explanation:

all angle degrees added up = 180 degrees as I said before.

180 = 102+48+M

180 = 150+M

M = 30

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What is the gcf of 25 and 90

Yuliya22 [10]

25 = 5^2
90 = 2 . 3 . 3 . 5

GCF is not as greedy as LCM.
GCF is just on a diet, so it takes the same number and the smallest amount.

25 and 90 both have 5.
5^2 or 5 ?
Take the smaller one.
GCF = 5

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3 years ago

Which number is a perfect square?<br> оооо

puteri [66]

Answer:

1, 4, 9, 16, 25, etc

Step-by-step explanation:

a perfect square is a whole number multiplied by itself. it can be written with the notation ^2

to find a perfect square, simply square or bring to the 2nd power, any whole number

for example 9^2

this means that 9 is multiplied by ITSELF 2 times, it is NOT 9*2

it can also be written as 9*9=81

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3 years ago

Which is bigger or equal 6 gallons or 96 pints

svetlana [45]

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Step-by-step explanation:

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3 years ago

What is the area of the rectangle?

den301095 [7]

Answer:

$50\ units^{2}$

Step-by-step explanation:

Plot the figure to better understand the problem

see the attached figure

we know that

If the figure is a rectangle

then

$AB=CD \\AD=BC$

The area of the rectangle is equal to

$A=B*h$

where

B is the base

h is the height

the base B is equal to the distance AB

the height h is equal to the distance AD

Step 1

Find the distance AB

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-5,5)\\B(0,-5)$

substitute the values

$d=\sqrt{(-5-5)^{2}+(0+5)^{2}}\\d=\sqrt{(-10)^{2}+(5)^{2}}\\dAB=\sqrt{125}\ units$

Step 2

Find the distance AD

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-5,5)\\D(-1,7)$

substitute the values

$d=\sqrt{(7-5)^{2}+(-1+5)^{2}}\\d=\sqrt{(2)^{2}+(4)^{2}}\\dAD=\sqrt{20}\ units$

Step 3

Find the area of the rectangle

$A=AB*AD$

we have

$dAB=\sqrt{125}\ units\\dAD=\sqrt{20}\ units$

substitute

$A=\sqrt{125}*\sqrt{20}\\A=\sqrt{2,500}\\A=50\ units^{2}$

7 0

4 years ago