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3 years ago

How can you determine if a triangle on the coordinate plane is a right triangle?

Mathematics

2 answers:

tankabanditka [31]3 years ago

7 0

Answer:

You will know when two lines exactly verticle and horizontle meet together that one intersection will be a right angle it will be exactly 90 degrees.

stiv31 [10]3 years ago

5 0

You will know when two lines exactly verticle and horizontle meet together that one intersection will be a right angle it will be exactly 90 degrees.

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What is the exact value of <br> sin

Mamont248 [21]

It has to be one of the negative answers. I’m not sure which one but I am sure it’s a negative number. :)

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3 years ago

The shapes in this question are drawn on a centimetre grid.

xenn [34]

Answer:

A. 12 centimeters B. 4 centimeters C. 20 centimeters

Step-by-step explanation:

To find area you need to do the Height time the Length.

For A it is 3x4

For B it is 4x1

And for C it is 4x5

You get this equation by multiplying the amount of squares that the Height and Length measured!

Hope this helped!

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serg [7]

Answer 3:2

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3 years ago

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Simplify completely: 8x+4/x^3+23÷4x^2-10x-6/9-x^2

Helen [10]

Answer:

The simplified form is: $-x^2-2x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{2}{3}$

Step-by-step explanation:

To simplify the expression given we, need to open the brackets, and if there is power term. Then we need to group all the like terms and then arrange in the descending order of powers of the given expression.

Now the expression that is given to us is:

$8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2$

Here we will simplify it by grouping the like terms, as follows:

$8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2\\=-x^2+8x-10x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{6}{9}=-x^2-2x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{2}{3}$

So this is the required simplified form.

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3 years ago

The blade length is the radius of the circle formed by the area swept by the blades to the nearest square foot, what is the area

rewona [7]

Sorry i do not know wish i did

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