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Grace [21]
3 years ago
10

Elixir of acetaminophen contains 160 my per 5 milliliters. How much acetaminophen is needed to prepare 2 ounces of elixir?

Mathematics
1 answer:
AlekseyPX3 years ago
7 0
60 milliliters is equal to two ounces.
You might be interested in
A local Charity receives 1/3 of funds raised during a craft fair and bake sale. The total amount given to the charity was $137.4
Fed [463]

Answer:

The bake sale raised $412.35

Step-by-step explanation:

* Lets explain how to solve the problem

- A local Charity receives 1/3 of funds raised during a craft fair and

 bake sale

∴ The total amount given to the charity = 1/3 × the funds raised during

  a craft fair and bake sale

- The total amount given to the charity was $137.45

∴ The 1/3 of of funds raised during a craft fair and bake sale is $137.45

- Lets substitute the The total amount given to the charity in the

 equation above to find the funds raised during the bake sale

∴ 137.45 = 1/3 × the funds raised during the bake sale

- Multiply the both sides by 3

∴ 3 × 137.45 = the funds raised during the bake sale

∴ The funds raised during the bake sale = 412.35

* The bake sale raised $412.35

6 0
3 years ago
Write an equation for the line that is parallel to the given line and that passes through the given point.
lisabon 2012 [21]

Answer:

The correct answer is D) y = 1/2x - 14

Step-by-step explanation:

To find this equation, start with the slope of the original line. Since it is 1/2, the new line will also have that slope because parallel lines have the same slope. Now we can use this with the given point to find the equation.

y - y1 = m(x - x1)

y + 17 = 1/2(x + 6)

y + 17 = 1/2x + 3

y = 1/2x - 14

5 0
3 years ago
Simplify 18÷3x2+1 please
telo118 [61]

Answer:

the answer is gonna be

6x^2+1

7 0
3 years ago
Read 2 more answers
Every person in a certain group is either a Dodgers fan or a Yankees fan, but not both. The ratio of Yankees fans to Dodgers fan
Deffense [45]

Answer:

  E)  176

Step-by-step explanation:

The difference in ratio units is 5 -3 = 2. If one ratio unit changes sides, the ratio will be 4 : 4, or 1 : 1. Then one ratio unit represents 22 group members.

There are a total of 5+3 = 8 ratio units, so there are ...

  8 × 22 = 176

people in the group.

_____

<em>Check</em>

The original group has 5 × 22 = 110 Yankees fans and 3 × 22 = 66 Dodgers fans, for a total of 110+66 = 176 group members. If 22 switch sides, there will be 110-22 = 88 Yankees fans and 66+22 = 88 Dodgers fans, making the ratio ...

  88 : 88 = 1 : 1

7 0
3 years ago
Does anyone know how to do this?? Help please!!!!
Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

x^2 + 3 = 4*x + 4

Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

5 0
3 years ago
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