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Elina [12.6K]
3 years ago
8

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

istribution of the number of daily requests is bell-shaped and has a mean of 57 and a standard deviation of 7. Using the empirical rule (as presented in the book), what is the approximate percentage of lightbulb replacement requests numbering between 50 and 57
Mathematics
1 answer:
krek1111 [17]3 years ago
8 0

Answer:

34%

Step-by-step explanation:

According to the empirical rule, 68% of all of the data in a normal distribution falls within one standard deviation of the mean.

Applying to this particular case, 68% of the requests fall within (50 - 7) and (50+ 7). The percentage of requests from 43 to 50 is equal to the percentage of requests from 50 to 57.

Therefore, the percentage of light bulb replacement requests numbering between 50 and 57 is 68/2 =  34%.

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Which lists the steps in the correct order to find the median of this data set?
Fofino [41]

The median of the data set can be found as follows:

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Steps to find the median of the data set, 24, 16, 23, 30, 18, 29:

1. Put the numbers in order (from least to the greatest)

16, 18, 23, 24, 29, 30

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2 years ago
A team of scientist surveying a forest found that there were four oak trees for every 10 pine trees. If they counted 24 more pin
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Answer:

There are 16 Oak tree in the forest.

Step-by-step explanation:

Given: There are 4 Oak tree on every 10 pine trees.

           There are total 24 more pine tree than Oak tree.

 Using the ratio of trees to find the number of trees.

Lets assume there are total number of Oak tree be "x".

∴ Total number of Pine trees will be "x+24"

We know the ratio of Oak to Pine tree is 4:10 or \frac{4}{10}

⇒\frac{x}{x+24} = \frac{4}{10}

Multiplying both side by x+24

⇒ x= \frac{4(x+24)}{10}

Using distributive property of multiplication, distributing 4 with x and 24.

⇒ x= \frac{4x+96}{10}

Multiplying both side by 10

⇒ 10x= 4x+96

subtracting both side by 4x

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dividing both side by 6

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