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4 years ago

12

What is the solution of |x – 2| > –3

1 answer:

Amanda [17]4 years ago

6 0

Answer: The solution is the set of all real numbers (there are infinitely many solutions).

The reason why this is the case is because |x| is never negative. The smallest it can get is 0, which is larger than -3. That applies to |x-2| as well. So |x-2| is ALWAYS larger than -3 no matter what you pick for x. The smallest |x-2| can get is 0 and that happens when x = 2. Otherwise, the result is some positive value which is larger than -3.

So that's why |x-2| > -3 has infinitely many solutions. We can replace x with any real number we want, and the inequality would be true.

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lilavasa [31]

Answer:

slope=m

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Step-by-step explanation:

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3 years ago

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3 years ago

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3 years ago

David bought a pizza for $12.74 and four medium drinks. Define a variable and write an expression to represent the total amount

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3 years ago

Simplify the expression. Quantity cosecant of x to the power of two times secant of x to the power of two divided by quantity se

Art [367]

Answer:

D. 1

Step-by-step explanation:

We have the expression, $\frac{\csc^{2}x\sec^{2}x}{\sec^{2}x+\csc^{2}x}$

We get, eliminating the cosecant function,

$\frac{\sec^{2}x}{\frac{\sec^{2}x}{\csc^{2}x}+1}$

As, sinx is reciprocal of cosecx and cosx is reciprocal of secx,

i.e. $\frac{\sec^{2}x}{\frac{\sin^{2}x}{\cos^{2}x}+1}$

i.e. $\frac{1}{\cos^{2}x}\times \frac{\cos^{2}x}{\sin^{2}x+\cos^{2}x}$

Since, we know that, $\sin^{2}x+\cos^{2}x=1$

Thus,

$\frac{1}{\cos^{2}x}\times \frac{\cos^{2}x}{\sin^{2}x+\cos^{2}x}=1$

So, after simplifying, we get that the result is 1.

Hence, option D is correct.

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3 years ago