Option C
The distance of a spin of one full rotation is 31.4 feet
<em><u>Solution:</u></em>
Given that,
A circular merry-go-round has a radius of 5 feet
Radius = 5 feet
We have to find the distance of spin for one full rotation
Distance covered in 1 full of rotation is equal to circumference of circle
<em><u>The circumference of circle is given as:</u></em>
Where "r" is the radius
Thus the distance of a spin of one full rotation is 31.4 feet
Answer:
Step-by-step explanation:
<u><em>Let's check it using Pythagorean Theorem:</em></u>
Where c is the longest sides, a and b are rest of the 2 sides
1) 9 , 40 , 46
=>
=>
=> 2116 = 81 + 1600
=> 2116 ≠ 1681
So, this is not a Pythagorean Triplet
2) 16, 30 and 34
=>
=>
=> 1156 = 256 + 900
=> 1156 = 1156
No need to check more as we've found the one which is not a Pythagorean Triplet.
Answer:
The diagram with three triangles is not a good representation.
The other diagrams have three parts divided into 4 places. The diagram of the triangles only has 3 parts in each of the three triangles. The equation for that would be 3 divided by 1/3.
Step-by-step explanation:
Have a great rest of your day
#TheWizzer
