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Assoli18 [71]
3 years ago
10

Which of the following equations could be used to show the relationship

Mathematics
1 answer:
german3 years ago
7 0

Answer:

b and e

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

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Select all of the quantities that are correctly expressed in scientific notation
rjkz [21]
The first one and the last one
4 0
3 years ago
Find the exact value of cos 120° in simplest form with a rational<br> denominator.
IRINA_888 [86]

Given:

cos 120°

To find:

The exact value of cos 120° in simplest form with a rational  denominator.

Solution:

We have,

\cos 120^\circ

It can be written as

\cos 120^\circ=\cos (90^\circ+30^\circ)

\cos 120^\circ=-\sin 30^\circ             [\because \cos (90^\circ-\theta)=-\sin \theta]

\cos 120^\circ=-\left(\dfrac{1}{2}\right)             [\because \sin 30^\circ=\dfrac{1}{2}]

\cos 120^\circ=-\dfrac{1}{2}

Therefore, the exact value of cos 120° is -\dfrac{1}{2}.

7 0
2 years ago
Given h(x) = x^ - 2, what is the value of h(-3) ?<br><br> ^ = is exponent 2
ella [17]

Answer:

  • 1/9

Step-by-step explanation:

<u>Given</u>

  • h(x) = x^ - 2
  • h(-3) = ?

<u>Substitute x with -3</u>

  • h(-3) = (-3)^-2 = 3^-2 = 9^-1 = 1/9
3 0
3 years ago
Read 2 more answers
The ratio of footballs to total pieces of equipment is... and we have 2 baseballs and 6 footballs
kirza4 [7]

Answer:

1:3 ............... ......

3 0
3 years ago
An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten week
sergiy2304 [10]

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) =  (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

5 0
3 years ago
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