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castortr0y [4]
2 years ago
11

Polynomials math question

Mathematics
2 answers:
olya-2409 [2.1K]2 years ago
4 0
The answer is b I just took the whole test
sesenic [268]2 years ago
3 0

Answer:

It is B) monomial

Step-by-step explanation: Please brainliest if correct!

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5x+y=2 solve the literal equation for x
Ksenya-84 [330]

Answer:

\sf \: x =  -  \frac{1}{5} y +  \frac{2}{5}

Step-by-step explanation:

5x+y=2 solve the literal{It's called linear }equation for x

5x+y=2

Step 1: Add -y to both sides.

5x+y+−y=2+−y

5x=−y+2

Step 2: Divide both sides by 5.

5x/5=−y+2/5

x=−1/5y+2/5

5 0
1 year ago
Please help me with this problem i tried
mezya [45]

Answer:

I think the answer is 1280

4 0
3 years ago
Read 2 more answers
10. Is it possible to draw a three-sided figure where two of the sides are equivalent and two of the angles
Goryan [66]
The anwser is no its not possible
5 0
3 years ago
A rational number
evablogger [386]

Answer:

yes

Step-by-step explanation:

7 0
2 years ago
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Let R = [ 0 , 1 ] × [ 0 , 1 ] R=[0,1]×[0,1]. Find the volume of the region above R R and below the plane which passes through th
Bond [772]

The three vectors \langle0,0,1\rangle, \langle1,0,8\rangle, and \langle0,1,9\rangle each terminate on the plane. We can get two vectors that lie on the plane itself (or rather, point in the same direction as vectors that do lie on the plane) by taking the vector difference of any two of these. For instance,

\langle1,0,8\rangle-\langle0,0,1\rangle=\langle1,0,7\rangle

\langle0,1,9\rangle-\langle0,0,1\rangle=\langle0,1,8\rangle

Then the cross product of these two results is normal to the plane:

\langle1,0,7\rangle\times\langle0,1,8\rangle=\langle-7,-8,1\rangle

Let (x,y,z) be a point on the plane. Then the vector connecting (x,y,z) to a known point on the plane, say (0, 0, 1), is orthogonal to the normal vector above, so that

\langle-7,-8,1\rangle\cdot(\langle x,y,z\rangle-\langle0,0,1\rangle)=0

which reduces to the equation of the plane,

-7x-8y+z-1=0\implies z=7x+8y+1

Let z=f(x,y). Then the volume of the region above R and below the plane is

\displaystyle\int_0^1\int_0^1(7x+8y+1)\,\mathrm dx\,\mathrm dy=\boxed{\frac{17}2}

6 0
3 years ago
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