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2 years ago

Are the ratios 1:4 and 5:20 equivalent?

Mathematics

1 answer:

lukranit [14]2 years ago

8 0

Answer:

YES

Step-by-step explanation:

1:4 can be written as: $\frac{1}{4} \\
$ , and we know to make and equivalent fraction you multiply by a constant. so,

$\frac{1}{4} \\$ × $\frac{5}{5}$ = $\frac{5}{20}$ (5:20)

Hope this helps!

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Help meh please <br><br> -2/3 ÷ (-15)

pogonyaev

The answer is 0.04444... or 2/45. Whichever is more useful to you.

3 0

2 years ago

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If I plan to run 400 yards and I have completed 80%, how many yards do I have left?

Dimas [21]

Answer:

You have 80 yards left to run.

Step-by-step explanation:

To solve this problem, we first must realize that if you have completed 80% of the run, that you have 20% left (this is because 100%-80% = 20%).

Next, we must find 20% of 400 yards. We must remember that in math, the word "of" represents multiplication. We also know that 20% = 20/100 = 0.2.

To find 20% of 400 yards, we can perform the following operation:

20% * 400

0.2 * 400

Therefore, you have 80 yards left.

Hope this helps!

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3 years ago

The weights of dogs at a kennel are Normally distributed with a mean of 18 pounds and a standard deviation of 3.5 pounds.In whic

Ierofanga [76]

Answer:

P(x=25)=P(z=2)=0.9972 or 99.72%

Step-by-step explanation:

Mean = 18 pounds

Standard Deviation = 3.5 pounds

x= 25

We need to find P(x=25)

First, we need to find z-score using formula: $z-score=\frac{x-\mu}{\sigma}$

Finding z-score when x=25

$z-score=\frac{x-\mu}{\sigma}\\z-score=\frac{25-18}{3.5}\\z-score=2$

So, we need to find P(z=2)=P(x=25)

Looking at z-score table we can find P(z=2)

P(z=2)=0.9972 or 99.72%

So, P(z=2)=0.9972 or 99.72%

3 0

2 years ago

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A swimming pool at a park measures 9.75 meters by 7.2 meters.

neonofarm [45]

Answer:

Part a) The area of the swimming pool is $70.2\ m^2$

Part b) The total area of the swimming pool and the playground is $105.3\ m^2$

Step-by-step explanation:

Part a) Find the area of the swimming pool

we know that

The area of the swimming pool is

$A=LW$

where

L is the length side

W is the width side

we have

$L=9.75\ m\\W=7.2\ m$

substitute the values

$A=(9.75)(7.2)$

$A=70.2\ m^2$

therefore

The area of the swimming pool is $70.2\ m^2$

Part b) The area of the playground is one and a half times that of the swimming pool. Find the total area of the swimming pool and the playground

we know that

To obtain the area of the playground multiply the area of the swimming pool by one and a half

$\frac{1}{2}(70.2)=35.1\ m^2$

To obtain the total area of the swimming pool and the playground, adds the area of the swimming pool and the area of the playground

$70.2\ m^2+35.1\ m^2=105.3\ m^2$

therefore

The total area of the swimming pool and the playground is $105.3\ m^2$

6 0

2 years ago

Determine determine whether the following geometric series converges or diverges. if the series converges find its sum.

Lilit [14]

For starters,

$\dfrac{3^k}{4^{k+2}}=\dfrac{3^k}{4^24^k}=\dfrac1{16}\left(\dfrac34\right)^k$

Consider the $n$ th partial sum, denoted by $S_n$ :

$S_n=\dfrac1{16}\left(\dfrac34\right)+\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\cdots+\dfrac1{16}\left(\dfrac34\right)^n$

Multiply both sides by $\frac34$ :

$\dfrac34S_n=\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\dfrac1{16}\left(\dfrac34\right)^4+\cdots+\dfrac1{16}\left(\dfrac34\right)^{n+1}$