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DanielleElmas [232]
3 years ago
13

ABDE is a rectangle ED is 8cm BDC is a right-angled triangle bc is 4.5cm ABC is a straight line the area of the rectangle abde i

s 40cm^2 work out the area of the triangle BDC
also I need working out sooooooo

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

11.25cm^2

Step-by-step explanation:

given the area of the rectangle as 40cm^2, we can get the width of the rectangle.

Area =Length x width

40cm^2 = 8cm x width

we can divide both sides 8 to be left with the width

40/8 = 5cm

so the width is 5cm which is equal to the height of the triangle.

Area of BDC = 1/2 x base x height

BDC = 1/2 x 4.5 x 5

=11.25cm^2

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4 years ago
-40-8b=-6(1+7b) what’s the answer
Andre45 [30]

\text{Hey there!}

\mathsf{-40-8b=-6(1+7b)}\\\mathsf{SIMPLIFY\ both\ sides\ of\ your\ equation}\\\mathsf{-40-8b=-6(1+7b)}

\mathsf{Distribute\ the\ RIGHT\ side\ of\ the\ equation }\\\mathsf{Distribute [the\ formula\ is: a(b+c)=a(b)+a(c)=ab+ac]}\\\mathsf{-6(1)+(-6)}(7b)\\\mathsf{-6(1)=-6}\\\mathsf{-6(7b)=-42b}\\\mathsf{\rightarrow\ =-6+(-42b)}

\mathsf{-40-8b=-6+(-42b)}\\\mathsf{\rightarrow -8b-40=-42b-6}

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\mathsf{ADD\ by\ 40\ on\ your\ sides}\\\mathsf{34b-40+40=-6+40}\\\mathsf{Cancel\ out\ -40+40\ because\ that\ gives\ the\ result\ of\ 0}\\\mathsf{-6+40=34}\\\mathsf{\rightarrow New\ equation: 34b = 34}

\mathsf{DIVIDE\ both\ of\ your\ sides\ by\ 34}\\\mathsf{\dfrac{34b}{34}=\dfrac{34}{34}}\\\\\mathsf{Cancel\ out: \dfrac{34b}{34}\ because\ that\ gives\ you\ the\ result\ of\ 1b}\\\\\mathsf{Keep:\dfrac{34}{34}\ because\ it\ solves\ for\ b}\\\\\mathsf{\dfrac{34}{34}=34\div34=1}

\boxed{\boxed{\boxed{\boxed{\mathsf{Thus\ your\ answer\ is:\boxed{\boxed{\mathsf{b=1}}}}}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\dfrac{\frak{LoveYourselfFirst}}{:)}

8 0
3 years ago
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aleksley [76]

The values of OM, PN, ON and MN of the given square are;

OM = 46

PN = 23

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MN = 32.5

<h3>Pythagorean theorem</h3>

We are given;

LN = 46

  • Now, LN is the diagonal of the square and as such to get the sides of the square, we will make use of pythagoras theorem to get;

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For the diagonals;

LN = OM = 46

Also; LP = PN = 46/2 = 23

Read more about pythagoras theorem at;brainly.com/question/3317136

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Answer:

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