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DanielleElmas [232]
3 years ago
13

ABDE is a rectangle ED is 8cm BDC is a right-angled triangle bc is 4.5cm ABC is a straight line the area of the rectangle abde i

s 40cm^2 work out the area of the triangle BDC
also I need working out sooooooo

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

11.25cm^2

Step-by-step explanation:

given the area of the rectangle as 40cm^2, we can get the width of the rectangle.

Area =Length x width

40cm^2 = 8cm x width

we can divide both sides 8 to be left with the width

40/8 = 5cm

so the width is 5cm which is equal to the height of the triangle.

Area of BDC = 1/2 x base x height

BDC = 1/2 x 4.5 x 5

=11.25cm^2

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Step-by-step explanation:

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This issue would be that she calculated the ages with all representatives of both classes, such that she measured a whole population. It's not necessary.

In question 2:

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4 years ago
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