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iris [78.8K]
3 years ago
15

Integrate by parts or trig substition integral or anti derivative of dy/(y^2-16)

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
4 0

The simplest method probably would be to split up the integrand into partial fractions.

\dfrac1{y^2-16}=\dfrac18\left(\dfrac1{y-4}-\dfrac1{y+4}\right)

Then

\displaystyle\int\frac{\mathrm dy}{y^2-16}=\frac18\left(\int\frac{\mathrm dy}{y-4}+\int\frac{\mathrm dy}{y+4}\right)=\frac18\left(\ln|y-4|-\ln|y+4|\right)+C

=\dfrac18\ln\left|\dfrac{y-4}{y+4}\right|+C

=\ln\sqrt[8]{\left|\dfrac{y-4}{y+4}\right|}+C

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