Answer:
27.5 minutes
Step-by-step explanation:
Using,
R/R' = 2ᵃ/ᵇ------------------ Equation 1
From the equation,
R = mass of Element X before radioactive decay, R' = mass of element X after radioactive decay, a = Time taken, b = half life.
Given: R = 870 grams, R' = 154 grams, b = 11 minutes.
Substitute these values into equation 1
870/154 = 2ᵃ/¹¹
(870/154)¹¹ = 2ᵃ
Solve for a
2ᵃ = (5.649)¹¹
2ᵃ = 187061.26
Taking the logarithm of both side,
Log2ᵃ = Log(187061.26)
⇒ a = log(187061.26)/log2
a = 8.272/0.301
a = 27.5 minutes
Answer:
-5.6
Step-by-step explanation:
first distribute the 2.5
also convert the 2/5 to decimal (0.4) because it's hard to work with both decimal and fraction
2.5y + 2.5*0.4 = -13
2.5y +1 = -13
y = -14/2.5 = -5.6
If there is 8 boys then there is 12 girls because 2x4=8 boys so 3x4=12 girls.
Answer:
0.0838 (8.62%)
Step-by-step explanation:
defining the event G= an out-of-state transaction took place in a gasoline station , then the probability is
P(G) = probability that the transaction is fraudulent * probability that took place in a gasoline station given that is fraudulent + probability that the transaction is not fraudulent * probability that took place in a gasoline station given that is not fraudulent = 0.033 * 0.092 + 0.977 * 0.034 = 0.0362
then we use the theorem of Bayes for conditional probability. Defining also the event F= the transaction is fraudulent , then
P(F/G)=P(F∩G)/P(G) = 0.033 * 0.092 /0.0362 = 0.0838 (8.62%)
where
P(F∩G)= probability that the transaction is fraudulent and took place in a gasoline station
P(F/G)= probability that the transaction is fraudulent given that it took place in a gasoline station