Answer:
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Step-by-step explanation:
Let
x ----> the original length pf the piece of metal
y ----> the original width pf the piece of metal
we know that
----> equation A
The volume of the box is equal to

we have



substitute in the formula of volume
----> equation B
substitute equation A in equation B

solve for y


Solve the quadratic equation by graphing
using a graphing tool
The solution is y=21
Find the value of x

therefore
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Answer: −6c−j−9
Step-by-step explanation:
247.62 x 0.15 = 37.143
round to $37.14
I hope that helped :)
Divide the volume by the two measures. 728 ÷ 8 = 91 ÷ 6.5 = 14 so, the shoe box is we inches long.