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Nat2105 [25]
2 years ago
14

The data in this table represents a linear function.

Mathematics
1 answer:
Leviafan [203]2 years ago
7 0
Is 1/2 an answer? That’s what I keep getting
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Need Help 2 & 3 with inequalities!!!
Mrac [35]

Answer:

2. D

3. B

Step-by-step explanation:

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3 years ago
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3 years ago
If one container holds 55 balls, how many balls will nine containers hold? A. 395 B. 495 C. 455 D. 355
Anna35 [415]
<span>Simply multiply the number of balls that can fit in a single container by the total number of containers available. In our case, 55 (balls per container) * 9 (total number of containers) = 495. So the answer is B.</span>
6 0
3 years ago
Read 2 more answers
Help as soon as possible please
marta [7]

(3x + 5)° + (10x - 7)° = 180°

13x + (-2) = 180

13x = 180 + 2

13x = 182

x = 14

∠QRT = 3 * 14 + 5 = 42 + 5 = 47°

∠TRS = 10 * 14 - 7 = 140 - 7 = 133°

6 0
3 years ago
If there are 17 green marbles in a jar of 65 marbles, what is the probability of drawing 2 green marbles at random without repla
erastovalidia [21]

Answer:

Option b) \frac{17}{260}

Step-by-step explanation:

We are given the following information in the question:

Total number of marbles = 65

Number of green marbles = 17

We have to find the probability of drawing 2 green marbles at random without replacement.

Formula:

Probability = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

\text{P(Drawing 2 green marbles at random without replacement)} = \\\text{Probability of drawing }1^{st} \text{ green marble}\times \text{Probability of drawing }2^{nd} \text{ green marble}

\text{Probability of drawing }1^{st} \text{ green marble} = \displaystyle\frac{17}{65}\\\\\text{Probability of drawing }2^{nd} \text{ green marble} = \displaystyle\frac{16}{64}

\text{P(Drawing 2 green marbles at random without replacement)} =\displaystyle\frac{17}{65}\times \frac{16}{64}=\frac{17}{260}

Option b) \frac{17}{260}

5 0
3 years ago
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